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Black_prince [1.1K]
3 years ago
13

A soccer ball is kicked with a velocity of 25 m/s at an angle of 45° above the horizontal. What is the vertical component of its

acceleration as it travels along its trajectory?
Mathematics
1 answer:
garri49 [273]3 years ago
7 0
<h2>If we are considering upward direction as positive, vertical component of acceleration is -9.81 m/s².</h2>

Step-by-step explanation:

A soccer ball is kicked with a velocity of 25 m/s at an angle of 45° above the horizontal.

Here we need to find vertical component of its acceleration as it travels along its trajectory.

Vertical component of acceleration is acceleration due to gravity.

That is vertical component is 9.81 m/s² downward.

If we are considering upward direction as positive, vertical component of acceleration is -9.81 m/s².

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0
3 years ago
write a real-world problem in which you would need to find the number of units between -6 and 0 on a number line.
Mariulka [41]
Sam started with 0 dollars in his bank account. He charged his debit card for a sandwich that costs $6.00. If this was written on a number line. How many units would Sam to go to get back to where he started?
4 0
3 years ago
X<br> 0<br> 1<br> 2<br> 3<br> 4<br> y<br> ००<br> 12<br> 16<br> 20<br> 24
densk [106]
What to do?????????.......
4 0
3 years ago
The Hu family goes out for lunch, and the price of the meal is $58. The sales tax on the meal is 7%, and the family also leaves
Alexxx [7]

58  plus tip of .20  

so

58 times 0.2 = 11.6 is the tip

now we add tax (Presuming we son't tax the tip)

58 times 0.07 = 4.06 the tax

so its

58 + 11.6  + 4.06  = $73.66 total cost


8 0
3 years ago
Please help! Very confused,
Alex777 [14]
The answer is probably c
8 0
3 years ago
Read 2 more answers
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