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3 years ago

I Need Number 4 &' 6

Mathematics

1 answer:

adoni [48]3 years ago

4 0

4 is again c because you should put the 2 here 2a'2-1 so this is 2a'1 and this is 20 so
A2 is 20
Than you should again do this and find a3 ...

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If the battery costs $75 and has a life of 300 charge-discharge cycles, what is the cost of the energy in dollars per kilowatt h

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Step-by-step explanation:

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2 years ago

Are triangles ABC and EBD congruent? Explain

vladimir2022 [97]

Answer:

Yes, they are congruent!

Step-by-step explanation:

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3 years ago

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There is a line that includes the point (6,9) and has a slope of 3. What is its equation in

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2 years ago

Helpppppppppppppp meeeeeeeee

EleoNora [17]

Step-by-step explanation:

Hey there!

From the given figure;

An exterior angle is 127°.

To find: value of"X"

Now;

x+127° = 180°. [Being linear pair]

or, X = 180° - 127°

or, X = 53°

Therefore, the value of "X" is 53°.

Hope it helps!

5 0

3 years ago

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The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle).

The base and the height are our legs. We will use "H" for the hypotenuse

$H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17$

H = 17

If we decrease the base and the height by 2 centimeters, we have

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

$H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3$

$H' \approx 14.3$

So, the hypotenuse decreases $H - H' \approx 17 - 14.3 = 2.7$

3 0

3 years ago