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Verdich [7]
3 years ago
15

I Need Number 4 &' 6

Mathematics
1 answer:
adoni [48]3 years ago
4 0
4 is again c because you should put the 2 here 2a'2-1 so this is 2a'1 and this is 20 so
A2 is 20
Than you should again do this and find a3 ...
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Find the measures of the complementary angles that satisfy each case.
telo118 [61]

Answer:

first - 25 degrees, second - 65 degrees

Step-by-step explanation:

7 0
3 years ago
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Use substitution to determine the solution of the system of equations. Write the solution as an ordered pair.
zubka84 [21]
The answer is (6,4) x=6 y=4
5 0
2 years ago
Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
dean counted 10 red cards, 10 black catds, and 20 blue cards in a deck of cards. what is the ratio of red cards to all cards?
miv72 [106K]

Answer:

10:40

Step-by-step explanation:

10+10+20=40

10 red cards

4 0
2 years ago
Quadrilateral OPQR is inscribed inside a circle as shown below. Write a proof showing that angles O and Q are supplementary
denis-greek [22]
As anoutline, angles O and Q are inscribed angles which are measured by one-half of its intercepted arc.
angle O = 1/2 arc RQP
angle Q = 1/2 arc ROP

so arcs RQP and ROP together make up the entire circle which has 360 degrees.

so angles O and Q is 1/2 (360) = 180 degrees (supplementary angles).

6 0
2 years ago
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