$2\dfrac{1}{5}+1\dfrac{1}{10}=2+\dfrac{1}{5}+1+\dfrac{1}{10}=(2+1)+\left(\dfrac{1}{5}+\dfrac{1}{10}\right)\\\\=3+\left(\dfrac{1\cdot2}{5\cdot2}+\dfrac{1}{10}\right)=3+\left(\dfrac{2}{10}+\dfrac{1}{10}\right)=3+\dfrac{2+1}{10}=\boxed{3\dfrac{3}{10}}$

7 0

3 years ago

Someone plz help me with this

Phoenix [80]

Answer:

$5y^{6}\sqrt{2}$

Step-by-step explanation:

We want to simplify:

$\sqrt{50y^{12}}$

We rewrite as:

$\sqrt{2\times25 \times (y^{6})^2}$

We split the radical sign to obtain:

$\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}$

Simplify the square root for the perfect squares to get:

$5y^{6}\sqrt{2}$

Therefore the simplified form is: $5y^{6}\sqrt{2}$

8 0

3 years ago

"what is the binary equivalent of the decimal value 97?"

AleksandrR [38]

01100001 = 97 64+32+1=97 (if the leading bit is 0 it's usually not shown)
very easy
8 bits
Bit 1 Value 128
Bit 2 value 64
Bit 3 value 32
Bit 4 value 16
Bit 5 value 8
Bit 6 value 4
Bit 7 value 2
Bit 8 value 1

5 0

3 years ago

Why should you record a one in the tens column when regrouping in addition?

ICE Princess25 [194]

To keep the place holder

5 0

3 years ago