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Rufina [12.5K]
3 years ago
14

Plz help me well mark brainliest if correct........?

Mathematics
1 answer:
grigory [225]3 years ago
7 0

Answer:

can u retake the photo i cant see whole shapes ill answer the question when u post the new one

Step-by-step explanation:

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Is the function negative over (-6,-2)
MakcuM [25]
Yes, the function would be negative
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=Y%3D%5Cfrac%7B-2%7D%7Bx%7D%2B4" id="TexFormula1" title="Y=\frac{-2}{x}+4" alt="Y=\frac{-2}{x}+
Studentka2010 [4]

Part A: Vertical asymptote is x=0

Part B: Domain is \left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)

Part C: Horizontal asymptote is y=4

Part D: Range is \left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)

Explanation:

Part A: We need to determine the vertical asymptote

The vertical asymptote of a function can be determined by equating the denominator equal to zero.

Thus, we have,

x=0

Hence, the vertical asymptote is x=0

Part B: We need to determine the domain

The domain of the function is the set of all independent x - values for which the function is real and well defined.

Let us take the denominator and equate to zero.

Hence, we have, x=0

Therefore, the function is undefined at the point x=0

Thus, the domain of the function is \left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)

Part C: We need to determine the horizontal asymptote

The horizontal asymptote of the function can be determined by dividing the leading coefficient of the numerator by leading coefficient of the denominator.

Thus, we have, y=4

Hence, the horizontal asymptote of the function is y=4

Part D: We need to determine the range

The range of the function is the set of all dependent y -values of the function.

In other words, the range of the function can be determined by substituting the values for x.

Thus, we have,

\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)

Therefore, the range of the function is \left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)

6 0
3 years ago
What does x equal in the equation x-12+5x=24
Bess [88]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Suppose an arrow is shot upward on the moon with a velocity of 44 m/s, then its height in meters after tt seconds is given by h(
andreev551 [17]

Answer:

a. 38.19m/s

b. 38.605m/s

c. 38.937m/s

d. 39.0117m/s

e. 39.01917m/s

Step-by-step explanation:

The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}

Where:

x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval

a. Let's find h(3) and h(4) using the data provided by the problem:

h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f

The average velocity over the interval [3, 4] is :

v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s

b. Let's find h(3.5) using the data provided by the problem:

h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f

The average velocity over the interval [3, 3.5] is :

v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s

c. Let's find h(3.1) using the data provided by the problem:

h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f

The average velocity over the interval [3, 3.1] is :

v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s

d. Let's find h(3.01) using the data provided by the problem:

h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f

The average velocity over the interval [3, 3.01] is :

v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s

e. Let's find h(3.001) using the data provided by the problem:

h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f

v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s

7 0
3 years ago
Please help will mark brainliest
motikmotik

Answer:

16.5 cm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the other leg, then

x² + 13² = 21²

x² + 169 = 441 ( subtract 169 from both sides )

x² = 272 ( take the square root of both sides )

x = \sqrt{272} ≈ 16.5 cm ( to the nearest tenth )

3 0
3 years ago
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