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SVEN [57.7K]
3 years ago
6

Pleaseeeeee help !!

Mathematics
1 answer:
umka21 [38]3 years ago
4 0

A.\\-vp+40 < 95\qquad\text{subtract 40 from both sides}\\\\-vp < 55\qquad\text{change the signs}\\\\vp > -55\qquad\text{divide both sides by p}\\\\If\ p > 0\ then\ v>-\dfrac{55}{p}.\\\\If\ p < 0\ then\ v < -\dfrac{55}{p}

B>\\8w-3r=45\qquad\text{subtract 8 from both sides}\\\\-3r=-8w+45\qquad\text{change the signs}\\\\3r=8w-45\qquad\text{divie both sides by 3}\\\\r=\dfrac{8w-45}{3}

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How many 5-letter combinations can be created from the letters in the word "friendly"?
avanturin [10]

Answer:

1). infer 2). fired 3). filed 4). filer 5). elfin 6). nerdy 7). felid 8). finer 9). liner 10). lined 11). fiery 12). fiend 13). ferly 14). ferny 15). lindy 16). fined 17). lifer 18). field 19). redly 20). riley 21). riled 22). liney 23). rifle 24). drily 25). fried 26). diner 27). flier 28). flied 29). idler 30). deify 31). reify 32). yield 33). refly 34). dynel 35). edify 36). flyer

hope this helps :)

5 0
3 years ago
Help please! What is the answer ?
kupik [55]

Answer:

x < -3 or x > 3

second answer choice

Step-by-step explanation:

 The symbol "∨" between p and q represents a disjunction and can be replaced with the word "or" to turn p ∨ q into p or q.

Plug in x < -3 in for p and x > 3 for q, and now you have:

x < -3 or x > 3

which is the same as the second answer choice.

So, the answer is x < -3 or x > 3, or the second answer choice.

I hope you find my answer helpful.

7 0
3 years ago
Find the factor of each ff. <br>6z²+12z+18​
frosja888 [35]

Answer:

Step-by-step explanation:

6z² + 12z +1 8​

= 6(z^2 + 2z + 3).

That's it.

8 0
2 years ago
team has a 75% chance to win each of the 3 games they will play this week. Clare simulates the week of games by putting 4 pieces
kaheart [24]

Answer: 88

Step-by-step explanation:

check google if its wrong :)

6 0
3 years ago
PLEASE HELP ME SO I CAN MOVE ON FROM THIS TOPIC
ExtremeBDS [4]

Answer:

3rd option

Step-by-step explanation:

(\frac{f}{g} )(x)

= \frac{f(x)}{g(x)}

= \frac{2x^2-5x-3}{2x^2+5x+2} ← factorise numerator and denominator

= \frac{(x-3)(2x+1)}{(x+2)(2x+1)} ← cancel (2x + 1) on numerator/ denominator

= \frac{x-3}{x+2}

4 0
3 years ago
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