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NikAS [45]
3 years ago
12

A farmer sells 6.3 kg of apples and pears at the farmers .2/5 of this weight is apples and the rest is pears. How many kg of pea

rs did she sell at the farmers market
Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

4.8/5

Step-by-step explanation:

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Seriously need help!!????
Serga [27]
50 would be a good choice of answer
3 0
3 years ago
Can someone help me with this question please !
RoseWind [281]

Answer:

a) A triangle which the angles ratio is 1 : 2 : 3 is a 30º - 60º - 90º right triangle.

b) The shortest side is opposite to the shortest angle. So, we can calculate it using sin 30º.

$\text{sin}(30\º)=\frac{\text{Opposite side to x}}{19} $

$\frac{1}{2} =\frac{\text{Opposite side to x}}{19} $

$\text{Opposite side to x}= 9.5$

3 0
3 years ago
Read 2 more answers
A washer and a dryer cost 634 dollars combined. The washer cost 66 dollars less than the dryer. What is the cost of the dryer?
Nutka1998 [239]

Steps to Solve:

1.  634 / 2 = 317

2. 317 + 66 = 383

Answer:

A = $383

Notes:

Read the question, this problem is not that hard to solve!

8 0
3 years ago
Read 2 more answers
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0
3 years ago
These are the Other Ones
oee [108]
The answer to c is 0 and the answer to d is undefined

5 0
3 years ago
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