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vesna_86 [32]
3 years ago
8

Five bulbs of which three are defective are to be tried in two bulb points in a dark room

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

D 7

Step-by-step explanation:

Total no. of bulb= 5

no. of defected bulb= 3

no. of not defected bulb=2

Total no. of bulb combination = 5C2

=5!/2!(5-2)!

= 5!/2!3!

= 5×4×3×2×1/2×1×3×2×1

=120/12

=10

( since a room can be lighted with one bulb also)

total no. of bulb combination when room shall not light = 3C2

3!/2!(3-2)!

= 3!/2! 1!

= 3×2×1/2×1×1

= 6/2

=3

Now,

Total no. of trial when room shall light

=10-3

=7

Hence, number of trial when the room shall be lighted is 7 which is option d

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Answer:

  1. given
  2. addition property of equality
  3. addition property of equality
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Step-by-step explanation:

In step 2, -3x was added to both sides in accordance with the addition property of equality.

The same property lets you add 18 to both sides, as in step 3.

The division property of equality lets you divide both sides of the equation by 5. (Or, the multiplication property lets you multiply by 1/5.)

Swapping sides of the equal sign is allowed by the symmetric property of equality.

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Answer:

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3 years ago
IS THE FOLLOWING A SINUSOID OR NOT
Neko [114]
1. YES 2. NO, correct me if im wrong
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3 years ago
What is the scale factor use to create this dilation?
andrezito [222]
Given Info: "The dashed triangle is the image of the solid triangle"

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Answer:

88 ft^2

Step-by-step explanation:

For a rectangular prism with dimensions 1 ft by 8 ft by 4 ft, there are two opposite faces with dimensions

<em>1 ft by 8 ft, </em>

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