The line with slope negative-4/3 is steeper than the line with slope negative-2

1 answer:

6 0

The bigger absolute value slope will have the steeper line

so u have slopes of -4/3 and -2.....the absolute values of these are 4/3 (or 1 1/3) and 2........2 is larger then 4/3.....so the line with the slope of -2 is steeper then the line with the slope of -4/3......so the statement u wrote is false

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What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3

ivanzaharov [21]

Answer <u>(assuming it can be in point-slope form)</u>:

$y + 8 = \frac{1}{3} (x+6)$

Step-by-step explanation:

With the given information, we can use the point-slope formula, $y-y_1 = m (x-x_1)$ , to write the equation of the line. Substitute values for the $m$ , $x_1$ , and $y_1$ in the formula to do so.

The $m$ represents the slope, so substitute $\frac{1}{3}$ in its place. The $x_1$ and $y_1$ represent the x and y values of one point the line intersects, so substitute -6 for $x_1$ and -8 for $y_1$ . This gives the following answer and equation (just make sure to convert the double negatives into positives: