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mr Goodwill [35]

4 years ago

7

Helpppppp helpppppppp plssssssssss

1 answer:

Contact [7]4 years ago

5 0

Answer:

Isosceles the markings indicate the two sides are the same length

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What is the domain of the function represented by the graph?

il63 [147K]

Answer:

D

Step-by-step explanation:

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7 0

3 years ago

Sophia has read 75 pages in a 250-page book. What percent of the book has Sophia read?

yaroslaw [1]

If Sophia has read 75 pages and the book is 250
you take 75 and divide it by 250
your answer will be .3
witch would be 30% as a percentage

hope i helped Dosvedanya

4 0

4 years ago

Read 2 more answers

Raymond wants to make a boxer has a volume of 360 in.³ he wants the height to be 10 inches and the other two dimensions to be wh

QveST [7]

Volume = base area x height
360 = base area x 10
base area = 360 ÷ 10
base area = 36 in²

Possible dimensions :
1 x 36
2 x 18
3 x 12
4 x 9
6 x 6

There are 5 different size boxes that he can make.

8 0

4 years ago

How do I solve this???

iragen [17]

Answer:

6^10

Step-by-step explanation:

We know that a^ -b = 1/ a^b

So 1/ a^-b = a^b

1/6^-10 = 6^10

5 0

3 years ago

Read 2 more answers

Help will mark brainlist if it correct If each edge of a cube is increased by 2 inches, the

Anastasy [175]

Answer:

D. sum of these edges is increased by 24 inches -- True

Step-by-step explanation:

Given a cube and its edge is increased by 2 inches.

To study the effect of this increase in the Volume, area of each face, diagonal and sum of edges.

Solution:

Let the side of original cube = a inches.

Formula for volume of cube:

$V =side^3 = a^3$

If the side is increased by 2 inches, the side becomes (a+2) inches.

So, new volume, $V' = (a+2)^3$

Using the formula:

$(x+y)^3 =x^3+y^3+3xy(x+y)$

$V' = (a+2)^3 = a^3+8+3\times 2 \times a(a+2)=a^3+8+6a(a+2)$

So, $V' = V + 8+6a(a+2)$

Volume increased by 8+6a(a+2) [which is not equal to 8]

So, statement is false:

A. volume is increased by 8 cubic inches -- False

Each face in a cube is a square.

Area of each face, A = $side^2 = a^2$

New area, A' = $(a+2)^2$

Using the formula: $(x+y)^2 =x^2+y^2+2xy$

$A' = a^2+4+4a$

Area increased by 4+4a [which is not equal to 4 sq inches]

B. area of each face is increased by 4 square inches -- False

Diagonal of each face = $a\sqrt2$

Increase of 2 in the edge:

New diagonal = $(a+2)\sqrt2 = a\sqrt2+2\sqrt2$

So, increase of $2\sqrt2$ not 2.

C. diagonals of each face is increased by 2 inches -- False

There are 12 number of edges in a square.

So sum of all 12 edges = 12a

When edge is increased by 2, sum of all edges = 12(a+2) = 12a + <em>24</em>

An increase of 24.

D. sum of these edges is increased by 24 inches -- True

4 0

3 years ago