Find where the graph crosses the X axis
ex: graph crosses X axis at x=2 and x=6
factorization should be (x-2) and (x-6) for a quadratic
The third one pls mark me brainliest
Step-by-step explanation:
Wai 1unit+45
Cheryl 1unit
Zheng 4units+180
Altogether 6units+225=510
6units = 510-225
6units=285
1unit=285÷6
= $47.5
So Wai =47.5+45 = 92.5
Cheryl =47.5
Zheng =4×47.5+180 =370
370-47.5=$322.5
Answer $322.5
Answer:
i = 75.7°
h = 48.2°
Step-by-step explanation:
==>To find i, use the sine rule for finding angles: sin(A)/a = sin(B)/b
Where,
a = 7.2cm
sin(A) = i
b = 6.5cm
sin(B) = sin(61) = 0.8746
Thus:
sin(A)/7.2 = 0.8746/6.5
Multiply both sides by 7.2
sin(A) = (0.8746*7.2)/6.5
sin(A) = 0.969 (3 s.f)
A = i° = sin^-1(0.969) = 75.7 (3 s.f)
==>To find h, use the Cosine rule for angles:
Cos(C) = (a²+b²-c²)/2ab
cos(C) = h°, a = 4, b = 4.5, c = 3.5
a² = 16
b² = 20.25
c² = 12.25
cos(C) = (16+20.25-12.25)/(2*4*4.5)
cos(C) = 24/36
cos(C) = 0.667 (3 s.f)
C = h° = cos^-1(0.667) = 48.2° (3 s.f)
Answer:
B
Step-by-step explanation:
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