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3 years ago

6

What is 5p to the second power plus 7p to the second power

1 answer:

Sauron [17]3 years ago

3 0

The answer is 74. I'm 100% sure.

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X/6=9/20<br> What is the answer?

Whitepunk [10]

Step-by-step explanation:

$\frac{x}{6} = \frac{9}{20} \\$

$x \times 20 = 9 \times 6$

$20x = 54$

$x = \frac{54}{20} \\$

$x = 2.7$

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1 year ago

What does it mean when a researcher states that an observed effect or difference is significant with a confidence level of 99%?

icang [17]

Answer:

it affected more than half

Step-by-step explanation:

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3 years ago

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Help i need to ppooooppp

Daniel [21]

Answer: b

Step-by-step explanation: There was the same question on brainly and they said that the submarine sandwich one was right.

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3 years ago

What is the answer to <br><br> 0.25p + 1 ≤ 9 <br><br> ? please help

saw5 [17]

P is less than or equal to 32

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3 years ago

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This net can be folded to make a square pyramid. what is the surface area of the pyramid

givi [52]

Answer:

$85in^2$

Step-by-step explanation:

to find the surface area we need to find the followng areas:

area of the square

area of a triangle and multiply it by 4 (because there are 4 triangles)

And once we have those areas, we add them to find the surface area.

Area of the square:

the formula to find the area of a square is:

$a_{square}=l^2$

where $l$ is the length of the side: $l=5in$

thus the area of the square is:

$a_{square}=(5in)^2$

$a_{square}=25in^2$

Area of the triangles:

the are of 1 triangle is given by

$a_{triangle} =\frac{b*h}{2}$

where $b$ is the base of the triangle: $b=5in$ (the base of the triangle is the side of the square)

and $h$ is the height of the triangle: $h=6in$

thus, the area of 1 triangle is:

$a_{triangle} =\frac{(5in)*(6in)}{2}$

$a_{triangle} =\frac{30in^2}{2}$

$a_{triangle} =15in^2$

the area of the 4 triangles is (we multiply by 4):

$a_{4-triangles}=4(15in^2)$

$a_{4-triangles}=60in^2$

finally we add the area of the square and the area of the 4 triangles to find the total surface area:

$Surface=25in^2+60in^2$

$Surface=85in^2$

8 0

2 years ago