Question

Consider the quadratic function f(x) = x2 – 8x – 4. What is the value of the leading coefficient

Answer 1

Answer:

The answer is

the value of the leading coefficient is equal to $1$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$f(x)=x^{2} -8x-4$  

equate the function to zero

$x^{2} -8x-4=0$    

so

$a=1\\b=-8\\c=-4$

the value of the leading coefficient is equal to a

$a=1$

Answer 2

Easey
f(x)=ax^2+bx+c
leading coefient is a
f(x)=1x^2-8x-4
leading coefient is 1