Ok, so:
For Part A, we have: P(Z|A)=P(Z and A)/P(A)
And if we replace, we got:
P(Z|A) = (0.15)/(0.25) and this is equal to 0.6.
For Part B, we have: P(A|Z)=P(Z and A)/P(Z)
P(A|Z) = (0.15)/(0.73) and this is equal to 0.205.
Recall that a ⇒ b ≡ ¬a ∨ b.
• r ⇒ (p ∧ q) ≡ ¬r ∨ (p ∧ q)
In row C, q is false so p ∧ q false, and r is true so ¬r is false.
¬r ∨ (p ∧ q) ≡ false ∨ false ≡ false
• r ⇒ (p ∨ q) ≡ ¬r ∨ (p ∨ q) = p ∨ q ∨ ¬r
In each of rows A, C, and E, at least one of p or q is true, so
p ∨ q ∨ ¬r = true
• (q ∧ r) ⇒ p ≡ ¬(q ∧ r) ∨ p ≡ (¬q ∨ ¬ r) ∨ p = p ∨ ¬q ∨ ¬r
In row E, p is false and both q and r are true, so ¬q and ¬r are both false.
false ∨ false ∨ false = false
• (q ∨ r) ⇒ p ≡ ¬(q ∨ r) ∨ p ≡ (¬q ∧ ¬r) ∨ p
In row E, p is false and both q and r are true, so both ¬q and ¬r are false.
(¬q ∧ ¬r) ∨ p ≡ (false ∧ false) ∨ false ≡ false ∨ false ≡ false
Answer:
18.5
Step-by-step explanation:
In the above question, we are given the following values
Cumulative probability ( confidence interval) = 0.95 = 95%
Mean = 10.5
Standard deviation = 4.10
We are asked to find the value of x.
To solve for x , we would be using the z score formula.
z score = (x-μ)/σ,
where x is the raw score,
μ is the population mean
σ is the population standard deviation
z score was not given in the question, but we have our cumulative probability as 95%(0.95).
Using the appropriate table,
the z score for 95% confidence is z = 1.96.
Therefore,
z score = (x-μ)/σ,
1.96 = x - 10.5/4.10
Cross multiply
1.96×4.10 = x - 10.5
x = (1.96 × 4.10) + 10.5
x = 8.036 + 10.5
x = 18.536
Approximately to 1 decimal place
x = 18.5
A. All of the members of the PTA.
The answer would be about 21 dollars
