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creativ13 [48]
4 years ago
9

What is the angle JKM???

Mathematics
2 answers:
ANEK [815]4 years ago
5 0

Answer:

176°

Step-by-step explanation:

Since, KR bisects angle JKM, so, measure of angle JKM will be twice of the measure of angle RKM.

m\angle JKM = 2\times m\angle RKM \\ m\angle JKM = 2\times 88 \degree \\ \huge \red{ \boxed{ m\angle JKM = 176 \degree}}

ValentinkaMS [17]4 years ago
4 0

Answer:

90

will explain in details

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√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
Please help me with this *20 points*
zhannawk [14.2K]

Answer:

Part A : About 5,931

Part B : 5,930.8

Part C : Yes, because it rounded it to the nearest full number

5 0
4 years ago
La ecuación trigonométrica que no tiene solución es: a. cos x = 0 b. sen x = 0 c. sen x = -1 d. sen x = 1
s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

3 0
3 years ago
From a train station, one train heads north, and another heads east. Some time later, the northbound train has traveled 12 miles
tigry1 [53]

9514 1404 393

Answer:

  20 miles

Step-by-step explanation:

The north and east distances form the legs of a right triangle. The straight-line distance between the trains is the hypotenuse of that triangle. The Pythagorean theorem can be used to find the length of the hypotenuse (d).

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  d = √400 = 20

The two trains are 20 miles apart.

__

<em>Additional comment</em>

You may recognize the given distances are in the ratio 3 : 4.  You may recall that side ratios of 3 : 4 : 5 make a right triangle. If so, you recognize that the straight-line distance is (4 miles)×5 = 20 miles. (3:4:5 right triangles show up often in algebra and geometry problems, so might be something you want to look for.)

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3 years ago
Factor:<br><br> 7x²+3x-4<br> Plz ASAP
bogdanovich [222]
The answer is (7x-4)(x+1)
8 0
4 years ago
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