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creativ13 [48]
3 years ago
9

What is the angle JKM???

Mathematics
2 answers:
ANEK [815]3 years ago
5 0

Answer:

176°

Step-by-step explanation:

Since, KR bisects angle JKM, so, measure of angle JKM will be twice of the measure of angle RKM.

m\angle JKM = 2\times m\angle RKM \\ m\angle JKM = 2\times 88 \degree \\ \huge \red{ \boxed{ m\angle JKM = 176 \degree}}

ValentinkaMS [17]3 years ago
4 0

Answer:

90

will explain in details

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Please any one help me ​
Ulleksa [173]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Since it's a Trapezoid with its non - parallel sides equal to one another,

\qquad \sf  \dashrightarrow \:\angle A + \angle P = 180

[ By forming co - interior angle pair ]

\qquad \sf  \dashrightarrow \:\angle A +100 = 180

\qquad \sf  \dashrightarrow \:\angle A = 180 - 100

\qquad \sf  \dashrightarrow \:\angle A = 80

Now, similarly,

\qquad \sf  \dashrightarrow \:\angle A + \angle R = 180

\qquad \sf  \dashrightarrow \: \angle R + 80 = 180

\qquad \sf  \dashrightarrow \: \angle R  = 100

Similarly,

\qquad \sf  \dashrightarrow \angle K + \angle R = 180

\qquad \sf  \dashrightarrow \angle K + 100 = 180

\qquad \sf  \dashrightarrow \angle K  = 80

3 0
3 years ago
Read 2 more answers
Use Lagrange multipliers to find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Enter the dimens
Dima020 [189]

Answer:

(x,y,z) = (12,12,12) cm

Step-by-step explanation:

The box is assumed to be a closed box.

The surface area of a box of dimension x, y and z is given by

S = 2xy + 2xz + 2yz

We're to minimize this function subject to the constraint that

xyz = 1728

The constraint can be rewritten as

xyz - 1728 = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = 2xy + 2xz + 2yz - λ(xyz - 1728)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points, each of the partial derivatives is equal to 0.

(∂L/∂x) = 2y + 2z - λyz = 0

λ = (2y + 2z)/yz = (2/z) + (2/y)

(∂L/∂y) = 2x + 2z - λxz = 0

λ = (2x + 2z)/xz = (2/z) + (2/x)

(∂L/∂z) = 2x + 2y - λxy = 0

λ = (2x + 2y)/xy = (2/y) + (2/x)

(∂L/∂λ) = xyz - 1728 = 0

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

(2/z) + (2/y) = (2/z) + (2/x)

(2/y) = (2/x)

y = x

Also,

(2/z) + (2/x) = (2/y) + (2/x)

(2/z) = (2/y)

z = y

Hence, at the point where the box has minimal area,

x = y = z

Putting these into the constraint equation or the solution of the fourth partial derivative,

xyz - 1728 = 0

x³ = 1728

x = 12 cm

x = y = z = 12 cm.

7 0
3 years ago
Does -8x+8=0 have a solution ?
dusya [7]

Answer:

Yes it does. It is 1.

Step-by-step explanation:

Subtract 8 from both sides then divide both sides by -8 and you get 1.

5 0
3 years ago
Which two ratios represent qauntities that are proportional
Leokris [45]
Are there answer choices ?
6 0
3 years ago
What is the equation of the line h Th ya has a y intercept of (0,-3) and passes through the point (-9,-9)
Nikolay [14]

Answer:

The line equation is given as: 3 y = 2 x - 9

Step-by-step explanation:

Here, Y intercept   is at point ( 0.-3)

So, at x = 0, y = -3

or, C  = -3

Also, the point on the equation line is (x,y)  = (-9,-9)

Now, by <u>SLOPE INTERCEPT FORM</u> of a line equation,we get:

y = m x + C   :  m  = slope of line  ......... (1)

So, substituting the values of C and (x,y) , we get:

-9  = m (-9)  + (-3)  

or, -9 + 3  = - 9 m

or, m =  -6/-9  = 2/3

or, m = 2/3

Now, substitute the value of m back in to the line equation (1)

y = m x + C   \implies  y = (\frac{2}{3}) x - 3\\\implies 3y = 2x - 9

Hence, the line equation is given as: 3 y = 2 x - 9.

5 0
4 years ago
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