I believe the answer is y = -3x + 15
This is what I got from calculating it but I haven’t done this type of equation in a while
Simplify (x3 + 3x2 + 5x – 4) – (3x3 – 8x2 – 5x + 6)
The first thing I have to do is take that "minus" sign through the parentheses containing the second polynomial. Some students find it helpful to put a "1" in front of the parentheses, to help them keep track of the minus sign.
Here's what the subtraction looks like, when working horizontally:
(x3 + 3x2 + 5x – 4) – (3x3 – 8x2 – 5x + 6)
(x3 + 3x2 + 5x – 4) – 1(3x3 – 8x2 – 5x + 6)
(x3 + 3x2 + 5x – 4) – 1(3x3) – 1 (–8x2) – 1(–5x) – 1(6)
x3 + 3x2 + 5x – 4 – 3x3 + 8x2 + 5x – 6
x3 – 3x3 + 3x2 + 8x2 + 5x + 5x – 4 – 6
–2x3 + 11x2 + 10x –10
And here's what the subtraction looks like, when going vertically:
x
3
−(3x
3
+3x
2
−8x
2
+5x
−5x
−4
+6)
In the horizontal addition (above), you may have noticed that running the negative through the parentheses changed the sign on each and every term inside those parentheses. The shortcut when working vertically is to not bother writing in the subtaction sign or the parentheses; instead, write the second polynomial in the second row, and then just flip all the signs in that row, "plus" to "minus" and "minus" to "plus".
\
x
3
–3x
3
−2x
3
+3x
2
+8x
2
+11x
2
+5x
+5x
+10x
−4
–6
−10
Either way, I get the answer:
–2x3 + 11x2 + 10x – 10
Answer:
Consistent/Independent, Inconsistent, Dependent
Step-by-step explanation:
<u>Consistent/Independent:</u>
Where there's only one unique solution
<u>Inconsistent</u>
Where there is no solution
<u>Dependent</u>
Where the solution is dependent
Answer:
y = (x - 2)² + 9
Step-by-step explanation:
To obtain the equation in vertex form use the method of completing the square.
Add/ subtract ( half the coefficient of the x- term)² to x² - 4x
y = x² + 2(- 2)x + 4 - 4 + 13
= (x - 2)² + 9 ← in vertex form
