Say you have 3 cakes. How many cakes would you have eaten if you ate 1/3 of the three cakes? One, you have eaten one cake, out of the three you have.
How many cakes do you have left if you eat 2/3 of the three cakes? Two, you have eaten 2 cakes, and have 1 cake left.
It is a similar approach here, except the confusing part is working "forward", when you really have to work "backward". If you have driven 30 miles, and you have driven 2 parts out of the trip when there is 3 parts of the trip, how many miles have you driven? Hint: Dividing 30 by 2 gives you what fraction of the distance to Jeff's grandmother?
To find f(3), plug x = 3 in f(x),
∴ f(3) = 3(3)+1 = 9+1 = 10
Therefore, the ordered pair is (3,10)
For second one,
plug x = 10 in f⁻¹(x),
f⁻¹(10) = 10-1/3 = 9/3 = 3
Therefore, the ordered pair is (10,3)
Answer:
∠A=30°
Step-by-step explanation:
let's call the angle at the bottom B and the one next to the 130 C
∠A=3x-6
∠C=180-130= 50°
vertical angles are equal∠B =8x+4
∠A+∠C+∠B=180°
find x:
3x-6+50+8x+4= 180°
11x+48=180°
11x= 132
x=12
find ∠A
∠A=3x-6= 3(12)-6 =30°
3.071 X10^12. if you move the decimal place to the right 12 times it will end up behind the 3.
Answer:
6
Step-by-step explanation:
