Can anyone help out with these two questions?
1 answer:
To find f(3), plug x = 3 in f(x),
∴ f(3) = 3(3)+1 = 9+1 = 10
Therefore, the ordered pair is (3,10)
For second one,
plug x = 10 in f⁻¹(x),
f⁻¹(10) = 10-1/3 = 9/3 = 3
Therefore, the ordered pair is (10,3)
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