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KIM [24]
4 years ago
8

Find the area of the parallelogram.

Mathematics
2 answers:
Nadya [2.5K]4 years ago
6 0
It’s d cuz it has 14 of them
aliina [53]4 years ago
3 0
B 24 square units your welcome
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(10 points)Assume IQs of adults in a certain country are normally distributed with mean 100 and SD 15. Suppose a president, vice
vesna_86 [32]

Answer:

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Step-by-step explanation:

To solve this question, we need to use the binomial and the normal probability distributions.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability the president will have an IQ of at least 107.5

IQs of adults in a certain country are normally distributed with mean 100 and SD 15, which means that \mu = 100, \sigma = 15

This probability is 1 subtracted by the p-value of Z when X = 107.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{107.5 - 100}{15}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 probability that the president will have an IQ of at least 107.5.

Probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

First, we find the probability of a single person having an IQ of at least 130, which is 1 subtracted by the p-value of Z when X = 130. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{130 - 100}{15}

Z = 2

Z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

Now, we find the probability of at least one person, from a set of 2, having an IQ of at least 130, which is found using the binomial distribution, with p = 0.0228 and n = 2, and we want:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.9772)^{2}.(0.0228)^{0} = 0.9549

P(X \geq 1) = 1 - P(X = 0) = 0.0451

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

What is the probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130?

0.3085 probability that the president will have an IQ of at least 107.5.

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Independent events, so we multiply the probabilities.

0.3082*0.0451 = 0.0139

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

8 0
3 years ago
What is it a b c or d
Jlenok [28]

Answer:

b  is perbindic uler

Step-by-step explanation:

3 0
3 years ago
g find the 2 components of vector b = 2i + j - 3k, one parallel to a = 3i - j and another one perpendicular to a
nika2105 [10]

Answer:

The components of \vec{b} parallel and perpendicular to \vec {a} are \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j and \vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k, respectively.

Step-by-step explanation:

Let be \vec b = 2\,i+j-3\,k and \vec a = 3\,i-j, the component of \vec b parallel to \vec a is calculated by the following expression:

\vec b_{\parallel} = (\vec b \bullet \hat{a}) \cdot \hat{a}

Where \hat{a} is the unit vector of \vec a, dimensionless and \bullet is the operator of scalar product.

The unit vector of \vec a is:

\hat{a} = \frac{\vec {a}}{\|\vec a\|}

Where \|\vec {a}\| is the norm of \vec a, whose value is determined by Pythagorean Theorem.

The component of \vec{b} parallel to \vec {a} is:

\|\vec {a}\| = \sqrt{3^{2}+(-1)^{2}+0^{2}}

\|\vec {a}\| = \sqrt{10}

\hat{a} = \frac{1}{\sqrt{10}} \cdot (3\,i-j)

\hat{a} = \frac{3}{\sqrt{10}}\,i -\frac{1}{\sqrt{10}} \,j

\vec{b}\bullet \hat{a} = (2)\cdot \left(\frac{3}{\sqrt{10}} \right)+(1)\cdot \left(-\frac{1}{\sqrt{10}} \right)+(-3)\cdot \left(0\right)

\vec b \bullet \hat{a} = \frac{5}{\sqrt{10}}

\vec b_{\parallel} = \frac{5}{\sqrt{10}}\cdot \left(\frac{3}{\sqrt{10}}\,i-\frac{1}{\sqrt{10}}\,j  \right)

\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j

Now, the component of \vec {b} perpendicular to \vec{a} is found by vector subtraction:

\vec{b}_{\perp} = \vec {b}-\vec {b}_{\parallel}

If \vec b = 2\,i+j-3\,k and \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j, then:

\vec{b}_{\perp} = (2\,i+j-3\,k)-\left(\frac{3}{2}\,i-\frac{1}{2}\,j  \right)

\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k

4 0
3 years ago
Input in standard form the equation of the given line. The line that passes through (1, 1) and (3, 4)​
Nataly [62]

Your answer..

\small{\color{green}{\fbox{\textsf{\textbf{Answer}}}}}

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