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loris [4]
3 years ago
5

Find all solutions of the equation in the interval [0, 2pi) cosx (2 sinx+1)=0

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

x = pi/2 and 11pi/6

Step-by-step explanation:

Given the trigonometry expression

cosx (2 sinx+1)=0

This can be written in two forms as;

cosx  = 0 and 2sinx + 1 =  0

If cos x  = 0

x = arccos0

x = 90degrees

x = pi/2

Similarly

2sinx  + 1 = 0

2sinx = -1

sinx = -1/2

sinx  =-0.5

x = aarcsin(-0.5)

x = -30

Since sin is negative in the third and 4th quadrant

x = 270 + 30

x = 330degrees

x = 330pi/180

x = 11pi/6

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t\geq -14

The graph is shown in the figure attached.

Step-by-step explanation:

We need to solve the inequality 7\geq \frac{t}{-2} and graph the solution.

Solving the inequality: 7\geq \frac{t}{-2}

Switch sides and reverse the inequality:

\frac{t}{-2}\leq 7

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The graph is shown in the figure attached.

Keywords: Graph the inequality

Learn more about Graph the inequality at:

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Answer:

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5 0
2 years ago
5+8=6+7 true or false​
Romashka-Z-Leto [24]

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Step-by-step explanation:

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Merle has an offer from a credit card issuer for a 0% APR for the first 60 days and a 23.19% APR afterwards, compounded daily. W
Andreyy89

To find the rate add 1 to the annual rate divided by 365 days raised to the number of days left in the year minus 1.

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5+y+8

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