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3 years ago

Find all solutions of the equation in the interval [0, 2pi) cosx (2 sinx+1)=0

Mathematics

1 answer:

Vinil7 [7]3 years ago

6 0

Answer:

x = pi/2 and 11pi/6

Step-by-step explanation:

Given the trigonometry expression

cosx (2 sinx+1)=0

This can be written in two forms as;

cosx = 0 and 2sinx + 1 = 0

If cos x = 0

x = arccos0

x = 90degrees

x = pi/2

Similarly

2sinx + 1 = 0

2sinx = -1

sinx = -1/2

sinx =-0.5

x = aarcsin(-0.5)

x = -30

Since sin is negative in the third and 4th quadrant

x = 270 + 30

x = 330degrees

x = 330pi/180

x = 11pi/6

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3 years ago

Find the equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

Solution:

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that product of slopes of given line and slope of line perpendicular to given line is equal to -1

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

Thus the required equation of line is:

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

3 years ago

A bag contains white matarles and red marables,126 in total.The number of whit marables is 6 more than 5 than 5 times the number

denis-greek [22]

Answer:106

Step-by-step explanation:

Let number of white marbles be w

Let number of red marbles be r

w+r = 126---------1

w = 6 +5r-----------2

Put eqn 2 in eqn 1

6+ 5r + r = 126

6 + 6r = 126

6r = 120

r = 20

w = 6 +5r =6+100

= 106

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3 years ago