Before going into the details of the problem, let us first write down the most important information required for solving this problem.
1 ft = 12 inches
The distance that was crawled by Jack = 4 ft
= (4 * 12) inches
= 48 inches
The distance crawled by Christine = 3/4 of the distance crawled by Jack
= (3/4) * 48 inches
= 3 * 12 inches
= 36 inches
Then
The total distance crawled by the two children's = (48 + 36) inches
= 84 inches
So Jack and Christine together crawled a distance of 84 inches.
1 wallet= 5/32= 0.15625
Wallets for $80= 0.15625*80=12 wallets
(1/5) / 4.5 = 2 / m....1/5 mile to 4.5 minutes = 2 miles to m minutes
cross multiply
(1/5)(m) = (2)(4.5)
1/5m = 9
m = 9 * 5/1
m = 45 minutes <===
