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faust18 [17]
3 years ago
8

Round to the nearest thousand 38,315

Mathematics
2 answers:
loris [4]3 years ago
8 0
38,000 I hope this helps
scoray [572]3 years ago
8 0
38,000 I hope this helps!
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PLEASE HELP!!!<br>Simplify the expression and show your work<br><br>sqrt110x^17y^12
leonid [27]

Answer:

Step-by-step explanation:

10y2 - 17y + 12 = y + 16

10y2 - 17y + 12 - 16 = y

10y2 - 17y - 4 = y

10y2 -17y - y -4 = 0

10y2 -16y - 4 = 0

Now put formula

x = -b +- (square root) b2 - 4ac

                 2a

a = 10 b= -16 c= -4

y = -(-16) +- (square root) -16 - 4 (10) (-4)

                             2(10)

y = 16 +- (square root) -16 - 400

                                20

y = 16 +- (square root) -416

                         20

y = 16 +- 20.396

              20

Now this +- is the plus minus thingy in which two answers come

The first we will do is +

16 + 20.396                                         16 - 20.396

  20                                                             20

= 1.8198                                                           = -0.2198

6 0
3 years ago
PLEASE HELP ME AND DONT JOKE AROUND
VladimirAG [237]

Answer:

12

Step-by-step explanation:

Simplify  2+3 to 5.

7+3×  3 /5

Cancel 3

7+5

Simplify.

12

5 0
3 years ago
Read 2 more answers
PLEASE HELP...THANK YOU
Ierofanga [76]
The answer to your problem is C the third picture                                   

8 0
3 years ago
The numbers of students in the 8 schools in a district are given below. (Note that these are already ordered from least to great
Luba_88 [7]

Answer:The mean increases but the median stays the same.

Step-by-step explanation:

201 + 233 + 237 +255 +269+277+306 mean is 257 and median is 255

225 +233 + 237 +255 +269+277+306 mean is 260  and median is 255

8 0
3 years ago
If a varies directly as the cube root of B and if a equals to 3 when B equals to 64 find the formula connecting the variables he
Brrunno [24]

Answer:

a=k1\sqrt[3]{B}

B=125

Step-by-step explanation:

Given :

a=3

B=64

According to question

a ∝ \sqrt[3]{B}

therefore

a=k1 \sqrt[3]{B}........Eq(1)

K1=\frac{a}{\sqrt[3]{B} }......Eq(2)

Putting the value of a and B we get in Eq(2) we get

K1=\frac{3}{4}

Putting the value of k1 in Eq(1)

a=\frac{3}{4}\sqrt{B} .......................Eq(3)

putting the value of a=15/4 IN Eq(3) we get

\frac{15}{4}\ =\frac{3}{4} \sqrt[3]{B}  \\\\\sqrt[3]{B}\ =\ 5\\Cubing\  both\  side\  we\  get\\B=125

5 0
3 years ago
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