Answer:
Step-by-step explanation:
10y2 - 17y + 12 = y + 16
10y2 - 17y + 12 - 16 = y
10y2 - 17y - 4 = y
10y2 -17y - y -4 = 0
10y2 -16y - 4 = 0
Now put formula
x = -b +- (square root) b2 - 4ac
2a
a = 10 b= -16 c= -4
y = -(-16) +- (square root) -16 - 4 (10) (-4)
2(10)
y = 16 +- (square root) -16 - 400
20
y = 16 +- (square root) -416
20
y = 16 +- 20.396
20
Now this +- is the plus minus thingy in which two answers come
The first we will do is +
16 + 20.396 16 - 20.396
20 20
= 1.8198 = -0.2198
Answer:
12
Step-by-step explanation:
Simplify 2+3 to 5.
7+3× 3
/5
Cancel 3
7+5
Simplify.
12
The answer to your problem is C the third picture
Answer:The mean increases but the median stays the same.
Step-by-step explanation:
201 + 233 + 237 +255 +269+277+306 mean is 257 and median is 255
225 +233 + 237 +255 +269+277+306 mean is 260 and median is 255
Answer:
a=k1![\sqrt[3]{B}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BB%7D)
B=125
Step-by-step explanation:
Given :
a=3
B=64
According to question
a ∝ ![\sqrt[3]{B}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BB%7D)
therefore
a=k1
........Eq(1)
K1=
......Eq(2)
Putting the value of a and B we get in Eq(2) we get

Putting the value of k1 in Eq(1)
.......................Eq(3)
putting the value of a=15/4 IN Eq(3) we get
![\frac{15}{4}\ =\frac{3}{4} \sqrt[3]{B} \\\\\sqrt[3]{B}\ =\ 5\\Cubing\ both\ side\ we\ get\\B=125](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B4%7D%5C%20%3D%5Cfrac%7B3%7D%7B4%7D%20%5Csqrt%5B3%5D%7BB%7D%20%20%5C%5C%5C%5C%5Csqrt%5B3%5D%7BB%7D%5C%20%3D%5C%205%5C%5CCubing%5C%20%20both%5C%20%20side%5C%20%20we%5C%20%20get%5C%5CB%3D125)