B. "rolling a 3 on a die and getting heads on a coin toss"
Answer:
( About ) 1,099 pounds
Step-by-step explanation:
The force required to keep this truck from rolling down the hill is opposed by the force of friction, comparative to the 2600 pounds of force against this friction. It should be that this opposing force is at work more towards the bottom of this hill, and thus the question asks the magnitude of latter force to keep this truck idle -
|| F || = sin( 25 ) * ( Fg ) = sin( 25 ) * ( 2600 lb ) = ( About ) 1098.80748 pounds
<u><em>This can be rounded to a solution of 1099 pounds</em></u>
Hi there!
In order to set each equation equal to each other, we must have them both equal the same variable.
Rearrange the top equation to make it equal to y:
x - y = -4
Add 4 to both sides and add y to both sides:
x + 4 = y
Now, we can set both equations equal to each other:
x + 4 = 5(x + 1)² - 3
Begin solving by expanding the square binomial:
x + 4 = 5(x² + 2x + 1) - 3
Simplify:
x + 4 = 5x² + 10x + 5 - 3
x + 4 = 5x² + 10x + 2
Bring all terms to one side:
0 = 5x² + 9x - 2
Factor:
0 = (5x - 1)(x + 2)
Set the other factor equal to 0:
5x - 1 = 0
5x = 1
x = 1/5
Plug in this value of x into an original equation:
1/5 - y = -4
1/5 + 4 = y
1/5 + 20/5 = y
y = 21/5