Question

A table mat has a perimeter of 32 inches The width of the table mat is triple it’s length write equation find the length and width then write the area of the table mat

Answer 1

Answer:

Length of mat = 4 inches

Width of mat = 12 inches

Area of table mat = 48 square inches

Step-by-step explanation:

Given

Perimeter = P = 32

Let l be the length of the table mat and w be the width of table mat

According to given statement

$w = 3l$

The perimeter of a rectangular object is given by:

$P = 2(l+w)$

Putting w=3l and value of P

$32 = 2(l+3l)\\2(4l) = 32\\8l = 32$

Dividing both sides by 8

$\frac{8l}{8} = \frac{32}{8}\\l = 4$

So

Length = l = 4 inches

And

Width = 3l = 3*4 = 12

Now

$Area = l * w\\A = 4 * 12\\A = 48\ in^2$

Hence,

Length of mat = 4 inches

Width of mat = 12 inches

Area of table mat = 48 square inches