That number is impossible to round... It is probably already been rounded to the Highest form.
400,000 has not other numbers to round up or down (Unless you say 4 but then it would stay as it is)
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
2 10/16 or 2 5/8
Step-by-step explanation:
You can add the whole numbers first, so 1+1=2
Now add the remaining fractions: 5/16 +5/16=10/16.
2+10/16=2 10/16 or 2 5/8.
Answer:
d
Step-by-step explanation:
