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Natalija [7]
3 years ago
11

Write the equation 5x - y + 6 = 0 in standard form with integer coefficients.

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0
I'm pretty sure It's  5x - y = -6

Hope I helped!
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Which data is considered a out liner 40,35, 44,90,23,25,28,35
lana66690 [7]
90 is the outlier
for future reference, outliers are numbers much larger or much smaller than the other numbers in a set
for example
2,3,4,21,6
or 90,87,94,12,99
7 0
3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
A person jogs 1/2 miles in 1/12 hours. The person's speed is how many miles per hour?
ipn [44]

Answer:

6 miles per hour

Step-by-step explanation:

speed = distance/time

speed = 1/2÷1/12 which is the same as

1/2 x 12/1 = 6

6 miles per hour.

or ou could change the 1/2 to become 0.5

and the 1/12 to become 0.083333333

and divide 0.5 ÷ 0.083333333 = 6.000000024

rounded to one decima place become 6.0

6 miles per hour

5 0
3 years ago
Simplify (square root 3)(^5 square root 3)
Karo-lina-s [1.5K]

Answer:

3^{\frac{7}{10} }

Step-by-step explanation:

\sqrt{3} *\sqrt[5]{3} = 3^1/2 x 3^1/5 = 3^(1/2 +1/5) = 3^7/10

3 0
2 years ago
Read 2 more answers
(5x^5) - (80x^3)<br> factoring
elena55 [62]

Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

4 0
3 years ago
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