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4 years ago

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Which of the following situations discusses work in the scientific

1 answer:

marshall27 [118]4 years ago

8 0

I would say A depending on its end location because it you are walking at a constant velocity and conclude the walk exactly where you began, you have used energy, but no work has been done.
Not C because the object begins at ground level and is then lifted above 3 feet, which has a displacement of 3 feet in the y-direction (vertical) but no distance has been traveled.

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A certain humidifier operates by raising water to the boiling point and then evaporating it. Every minute 30 g of water at 20◦ C

Sveta_85 [38]

Answer:

The value of total energy needed per minute for the humidifier = 77.78 KJ

Explanation:

Total energy per minute the humidifier required = Energy required to heat water to boiling point) + Energy required to convert liquid water into vapor at the boiling point) ----- (1)

Specific heat of water = 4190 $\frac{J}{kg k}$

The heat of vaporization is = 2256 $\frac{KJ}{kg}$

Mass = 0.030 kg

Energy needed to heat water to boiling point = $m c ( T_{2} - T_{1} )$

Energy needed to heat water to boiling point = 0.030 × 4.19 × (100 - 20)

Energy ( $E_{1}$ ) = 10.08 KJ

Energy needed to convert liquid water into vapor at the boiling point

$E_{2}$ = 0.030 × 2256 = 67.68 KJ

Thus the total energy needed E = $E_{1}$ + $E_{2}$

E = 10.08 + 67.68

E = 77.78 KJ

This is the value of total energy needed per minute for the humidifier.

9 0

4 years ago

Please help!!!!!!!!!!!!!!!!

Serjik [45]

Answer:

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Explanation:

where de numbers at

4 0

3 years ago

Someone help please I am suffering from these

seropon [69]

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3 0

4 years ago

An Argon laser (λ = 5.0×102nm) shines down a silica glass fiber-optic cable with index of refraction 1.46. What is the speed of

Yanka [14]

Answer:

The speed of the laser light in the cable, $c_f=2.1\times 10^8\ m/s$

Explanation:

It is given that,

Wavelength of Argon laser, $\lambda=5\times 10^2\ nm=5\times 10^{-7}\ m$

Refractive index, n = 1.46

Let $c_f$ is the speed of the laser light in the cable. The speed of light in a medium is given by :

$c_f=\dfrac{c}{n}$

$c_f=\dfrac{3\times 10^8\ m/s}{1.46}$

$c_f=2.05\times 10^8\ m/s$

or

$c_f=2.1\times 10^8\ m/s$

So, the speed of the laser light is $2.1\times 10^8\ m/s$ . Hence, this is the required solution.

4 0

4 years ago

Read 2 more answers

A satellite that is in a circular orbit 230 km above the surface of the planet Zeeman-474 has an orbital period of 89 min. The r

ehidna [41]

Answer:

Mass of the planet = 6.0 × $10^{24}$

Explanation:

Time period = 2π (R + h) / v

Orbital speed (v) = √GM / (R + h)

T² = 4π² (R + h)² / (GM/ (R + h))

= 4π² (R + h)³ / GM

making m the subject of the formula

m = 4π² (R + h)³ / GT²

= 4π² ( 6.38 × $10^{6}$ + 230 × 10³ )³ / ( 6.67 × $10^{-11}$ ) × (89 × 60)²

= 4π² ( 6610000)³ / ( 6.67 × $10^{-11}$ ) × (89 × 60)²

= 5.99 × $10^{24}$

= 6.0 × $10^{24}$

5 0

3 years ago