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3 years ago

The picture shows a device used to produce

Physics

1 answer:

lesya [120]3 years ago

6 0

It would be wind energy

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Which shows the correct order of events after the big bang occurred? strong force separated from the unified force, inflationary

LUCKY_DIMON [66]

Answer:

C) gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed

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3 years ago

How could glacial marks on one continent be similar to glacial marks on another continent far away?

BigorU [14]

Answer:

Plate Tectonics

Explanation:

Plate tectonics is the scientific theory that the continents move around due to due plate tectonics and the movement of magma under the crust. This explains why some fossils of the same kind are found on other continents, and same goes for the Glacial Marks.

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4 years ago

How many significant figures does 50.003 00 have?

Serhud [2]

5 sig figs I think that

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3 years ago

The force required to maintain an object at a constant velocity in free space is equal to

alex41 [277]

Answer:

The force required to maintain an object at a constant velocity in free space is equal to Zero.

7 0

3 years ago

An automobile whose speed is increasing at a rate of 0.800 m/s2 travels along a circular road of radius 10.0 m.

Ket [755]

(a) $a_t = 0.800 m/s^2$

The tangential acceleration component of the car is simply equal to the change of the tangential speed divided by the time taken:

$a_t = \frac{\Delta v}{\Delta t}$

This rate of change is already given by the problem, 0.800 m/s^2, so the tangential acceleration of the car is

$a_t = 0.800 m/s^2$

(b) $a_c = 0.9 m/s^2$

The centripetal acceleration component is given by

$a_c = \frac{v^2}{r}$

where

v is the tangential speed

r is the radius of the trajectory

When the speed is v = 3.00 m/s, the centripetal acceleration is (the radius is r = 10.0 m):

$a_c = \frac{(3.00 m/s)^2}{10.0 m}=0.9 m/s^2$

(c) $1.2 m/s^2, 48.4^{\circ}$

The centripetal acceleration and the tangential acceleration are perpendicular to each other, so the magnitude of the total acceleration can be found by using Pythagorean's theorem:

$a=\sqrt{a_t^2+a_c^2}=\sqrt{(0.8 m/s^2)^2+(0.9 m/s^2)^2}=1.2 m/s^2$

and the direction is given by:

$tan \theta =\frac{a_c}{a_t}=\frac{0.9 m/s^2}{0.8 m/s^2}=1.125\\\theta=tan^{-1}(1.125)=48.4^{\circ}$

where the angle is measured with respect to the direction of the tangential acceleration.

4 0

3 years ago