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8090 [49]
3 years ago
11

After an extruded feature has been created, you can always go back and edit the feature. When you edit an existing extrude featu

re, __________ cannot be changed from the Extrude PropertyManager?
Computers and Technology
1 answer:
Pani-rosa [81]3 years ago
3 0

Answer:

After an extruded feature has been created, you can always go back and edit the feature. When you edit an existing extrude feature, <u>the shape of the sketch profile</u> cannot be changed from the Extrude Property Manager.

<u>Extrude PropertyManager</u>

A tool that is used to draw different sketch. The sketches are related to different fields. Extrude property manager is used to edit the sketch, delete some objects form the sketch but we cannot edit the shape of the sketch profile.

<em>In this tool we can edit every thing but cannot edit the shape of the sketch profile.</em>

You might be interested in
What is the advantage of using the Publish Online option for sharing a calendar? It creates a web version that can be viewed by
kotykmax [81]

Answer:

its D. it allows a user outside an organization to view the calendar.

Explanation:

i just got it right on edge 2020.

7 0
3 years ago
Read 2 more answers
1) Which forms are NOT appropriate to use for affirmations in Full Verbatim?
Oliga [24]

NOT appropriate to use for affirmations in Full Verbatim are :

d) Mm

e) Ammm

f) Aha

Explanation:

  • In verbatim transcription, interviews are transcribed word for word, and sound for sound.  Every um, uh, laugh, and sound must be recorded for posterity.

These are the preferred spellings of typical utterances:

  1. Affirmative: uh-huh, mm-hmm, yeah.
  2. Don't use: um-hum, um-hmm, uh-hum

  • Full verbatim refers to a transcript that includes absolutely everything that is said, exactly how the speakers say it. This means we include all ums, uhs, grammatical and vocabulary mistakes, false starts and repetitions - everything.
  • Verbatim is defined as an exact repetition without changing the words. An example of verbatim is when you quote someone exactly without changing anything.
3 0
3 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
3 years ago
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
A digital certificate confirms that the macro created by the signer has not been altered since the digital certificate was creat
Nesterboy [21]

Answer: False

Explanation:

Digital certificate is defined as entity identification in digital form that is used by a user or firms to share their information along with authentication and security. It uses public key cryptographic technique and so it is also know as public key certificate.

  • Digital signature is the signature that is done digitally to secure data or document.It maintains security of the content present  in message of information that is being exchanged through e-signature.It follows encryption technique for maintaining authenticity.
  • Therefore, digital signature is the signing feature that protects macro after being made to maintain its authenticity.
  • Thus, the given statement is false.
3 0
3 years ago
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