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Tema [17]
3 years ago
14

Solve each equation for the variable in red #11

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
I can’t see the picture
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Can somebody help me with this :) ??
rjkz [21]

Answer:

A. (5,9)

Step-by-step explanation:

First, you need to reflect across the line of reflection. Since the point is 7 units from the line y=2 from one side, it will be 7 units away when it is reflected. 2+7=9, so the reflected coordinates of the point are (-2,9). For the glide translation, you slide the point 7 units to the right, placing it at the final location of (5,9). Hope this helps!

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Valentin [98]

Remark

At first glance, one would think this problem isn't possible. But if you use the magnifying glass, you see that it is.

Solve

25 carrots puts you somewhere to the left of the shaded area, so C and D are both wrong.

That leaves you with A or B. You need 30 carrots (or just very slightly less) at least to solve this problem. The way to distinguish between A and B is to look at the line that goes from lower right to upper left. When you magnify this graph, you see that at 30 carrots the line or boundary goes through 20 cucumbers. 21 is just very slightly above that and 25 is far above the other line. 21 cucumbers is the only possible right answer for the number of cucumbers. 25 is too high. B is wrong. The answer is A.

 

4 0
3 years ago
A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
Trudy bought a $40 prepaid long distance card. For every minute hat she talks, &amp;0.25 is deducted from her balance on the car
bezimeni [28]
The x intercept is the amount of money she has and I don't know what it is.... sorry. I knew what it stood for though. 
8 0
3 years ago
Evaluate the expression 3.14(a2 + ab) when a = 4 and b = 3. (Input decimals only, such as 12.71, as the answer.)
Natasha2012 [34]

Answer:

87.92

Step-by-step explanation:

3.14(a² + ab)  where  a = 4  and  b = 3

Plug the given numbers into the appropriate values.  Remember to follow PEMDAS.

3.14((4)² + (4)(3))

3.14(16 + 12)

3.14(28)

87.92

5 0
3 years ago
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