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lozanna [386]
3 years ago
6

HELP??????????????????!!!!!!!!!!!!!

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

the answer is 4

Step-by-step explanation:

thank you come again

Travka [436]3 years ago
4 0
The answer simplify is 4
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Answer please I need it ASAP
djverab [1.8K]

Answer:

answer what???

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4%20-%203x%20%3D%206" id="TexFormula1" title="4 - 3x = 6" alt="4 - 3x = 6" align="absmiddle" c
cestrela7 [59]
Answer is
Isolate the variable by dividing each side that don’t contain a variable
X = -2/3
Decimal form -0.6
4 0
3 years ago
The answer is below PLEASE HELP IM BEING TIMED I WILL MARK BRAINLIEST IF RIGHT
Fudgin [204]
15x+30y-220
Here is the work:

3 0
3 years ago
Quotient + remainder <br> I need help I would have 20 points
nexus9112 [7]

We want to compute

\dfrac{-5x^4+4x^3-20x^2+15x-16}{-x^2-3}

The goal is to write it in the following form:

-5x^4+4x^3-20x^2+15x-16=Q(x)(-x^2-3)+R(x)

First step: How many "copies" of -x^2 does -5x^4 contain? We can write -5x^4=(-x^2)(5x^2), so the answer is 5x^2 copies.

If we distribute 5x^2 to -x^2-3, we get

5x^2(-x^2-3)=-5x^4-15x^2

If we were done, then this product would have matched the numerator at the start. But it doesn't; there are still some terms that need to vanish. In particular, we still have to account for

(-5x^4+4x^3-20x^2+15x-16)-(-5x^4-15x^2)=4x^3-5x^2+15x-16

Second step: How many copies of -x^2 can we find in 4x^3? Well, 4x^3=(-4x)(-x^2), so the answer is -4x. Then

(5x^2-4x)(-x^2-3)=-5x^4+4x^3-15x^2+12x

but this still doesn't match the original numerator. We still have to deal with

(-5x^4+4x^3-20x^2+15x-16)-(5x^2-4x)(-x^2-3)=-5x^2+3x-16

Third step: How many copies of -x^2 can we get out of -5x^2? -5x^2=5(-x^2). Then

(5x^2-4x+5)(-x^2-3)=-5x^4+4x^3-20x^2+12x-15

This also doesn't match the original numerator. We have a difference between what we have and what we want of

(-5x^4+4x^3-20x^2+15x-16)-(5x^2-4x+5)(-x^2-3)=3x-1

But we also can't divide 3x into chunks of -x^2, and we can't continue the division algorithm.

Our final answer would be

\dfrac{-5x^4+4x^3-20x^2+15x-16}{-x^2-3}=5x^2-4x+5+\dfrac{3x-1}{-x^2-3}

For the second problem, you should find

\dfrac{-15x^3-13x+4}{5x^2+2}=-3x+\dfrac{-7x+4}{5x^2+2}

4 0
3 years ago
Please help!!!!! i need help so bad!!!!!!!!!!!!!!!!!!!!
Cerrena [4.2K]
Number 1. C
Number 2.C
Number 3.C
Number 4.A
Number 5.A
5 0
3 years ago
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