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jeyben [28]
4 years ago
12

Need answers for 1-6

Mathematics
2 answers:
UkoKoshka [18]4 years ago
5 0
Sorry am not able to help all but hope this will help

likoan [24]4 years ago
3 0
I think that #1 is 65 degrees
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Camille uses a 20% off coupon when buying a sweater that costs $47.99. If she also pays 6% sales tax on the purchase, how much d
dezoksy [38]
First calculate what the coupon does for Camille
so multiply %20 by the cost or .2(47.99)=9.598 which rounds to  9.60 meaning she still paid $38.39
Then calculate sales tax by multiplying her clearance price by %6 and adding it on the cost
.06(38.39)= 2.3034 which rounds to $2.30 in tax.
Add that onto the clearance price 38.39+2.30=$40.69
So her total cost was $40.69
3 0
4 years ago
Read 2 more answers
Which equation represents a line that passes through (5,4) with a slope of 2∕5?
abruzzese [7]
The answer is y = 2/5x + 2
5 0
3 years ago
Assume that a chocolate bar consists of n squares arranged in a rectangular pattern. The entire bar, a smaller rectangularpieceo
motikmotik

Step-by-step explanation:

Claim:

it takes n - 1 number of breaks to break the bar into n separate squares for all integers n.

Basic case -> n = 1

The bar is already completely broken into pieces.

Case -> n ≥ 2

Assuming that assertion is true for all rectangular bars with fewer than n squares. Break the bar into two pieces of size k and n - k where 1 ≤ k < n

The bar  with k squares requires k − 1 breaks and the bar with n − k squares

requires n − k − 1 breaks.

So the original bar requires  1 + (k−1) + (n−k−1) breaks.

simplifying yields,

1 + k − 1 + n − k − 1

1 - 1 + n - 1

n - 1

Therefore, we proved as we claimed that it takes n - 1 breaks to break the bar into n separate squares.

8 0
3 years ago
A recipe calls for 4 cups of sugar and 16 cups of water. If the recipe is reduced, how many cups of water should be used with 1
Radda [10]
Divide the recipe by 4. You need 4 cups of water.
5 0
3 years ago
Need help pls someone
dimaraw [331]

\sqrt[3]{250a^{11}}=\sqrt[3]{125\cdot2a^{2+9}}=\sqrt[3]{125}\cdot\sqrt[3]{2a^2\cdot a^9}=5\sqrt[3]{2a^2}\cdot\sqrt[3]{a^9}\\\\=5\sqrt[3]{2a^2}\cdot\sqrt[3]{a^{3\cdot3}}=5\sqrt[3]{2a^2}\cdot\sqrt[3]{(a^3)^3}=5\sqrt[3]{2^2}\cdot a^3\\\\=\boxed{5a^3\sqrt[3]{2a^2}}

7 0
4 years ago
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