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padilas [110]
3 years ago
5

Solve for x. Please answer correctly !!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
vlada-n [284]3 years ago
4 0
For this question answer is x=8
kvasek [131]3 years ago
4 0

Sum of the angles on a line is 180

(6x + 4) + 90 + (5x - 2) = 180 \\ 11x + 92 = 180 \\ 11x = 180 - 92 \\ 11x = 88 \\ x =  \frac{88}{11}  \\  \\ x = 8

Hope this will help....

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HELP DUE SUPER SOON!!
kow [346]

Answer:

2022 students

Step-by-step explanation:

Since 18 out of 270 students speak three or more languages, a prediction would be 30,330 x 18/270 = 2,022 students

6 0
3 years ago
Use the following function to find the value of each operation.
Murljashka [212]
<h2>Evaluating Composite Functions</h2><h3>Answer:</h3>

w(f(m(2))) = 593

<h3>Step-by-step explanation:</h3>

We can write how w(f(m(x))) will be defined but that's too much work and it's only useful when we are evaluating w(f(m(x))) with many inputs.

First let's solve for m(2) first. As you read through this answer, you'll get the idea of what I'm doing.

Given:

m(x) = -4x +1

Solving for m(2):

m(2) = -4(2) +1 \\ m(2) = -8 +1 \\ m(2) = -7

Now we can solve for f(m(2)), since m(2) = -7, f(m(2)) = f(-7).

Given:

f(x)=3x-1

Solving for f(-7):

f(-7)=3(-7)-1 \\ f(-7) = -21 -1 \\ f(-7) = -22

Now we are can solve for w(-22). By now you should get the idea why w(f(m(2))) = w(-22).

Given:

w(x) = x^2 -5x -1

Solving for w(-22):

w(-22) = (-22)^2 -5(-22) -1 \\ w(-22) = 484 -5(-22) -1 \\ w(-22) = 484 +110 -1 \\ w(-22) = 593

8 0
3 years ago
write an eqution in slope intercept form for the line that has the given slope and y intercept: m=-5 and b=-10
Karolina [17]

Answer:

y= -5x + -10

Hope this helps

8 0
4 years ago
(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

5 0
1 year ago
Which choice is equivalent to the product below when x &gt; 0?
anastassius [24]

The product below is equivalent when x > 0 is <u>1/9</u>

       

<h3>Resolution - Explanation</h3>

Square root is a real number x multiplied by itself - which results in a perfect value, where it is possible to calculate the real proof (which is the square root).

             

Given the expression, \large \sf \sqrt{\dfrac{1}{x^{2} } }  \cdot \sqrt{\dfrac{x^{2} }{81} }, first step: we will calculate the root of the numerator and denominator of this fraction:

<u />

<u />\\\large \sf \sqrt{\dfrac{1}{x^{2} } }  \cdot \sqrt{\dfrac{x^{2} }{81} }

\large \sf \dfrac{\sqrt{1} }{\sqrt{x^{2} } }  \rightarrow \dfrac{1}{x}

\large \sf \dfrac{\sqrt{x^{2} } }{\sqrt{81 } }  \rightarrow \dfrac{x}{9}\\\\

Step two: rearranging the expression and canceling the common factors x, we will have,:

\\\large \sf \dfrac{1}{\not x} \cdot \dfrac{\not x}{9}

\pink{\boxed{\large \sf \dfrac{1}{9} }}\\

Therefore, the final answer to this multiplication will be 1/9.

6 0
2 years ago
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