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Savatey [412]
3 years ago
8

G(x) = 3(x - 8) Find g(-2)

Mathematics
1 answer:
shutvik [7]3 years ago
7 0

Answer:

Step-by-step explanation:

if g(x)=3x-8

replace x with -2

g(-2)=3(-2)-8=-6-8=-14

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How do you write 25/20 as a percentage
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\dfrac{25}{20}=\dfrac{25\cdot5}{20\cdot5}=\dfrac{125}{100}=1\dfrac{25}{100}=1.25=1.25\cdot100\%=\boxed{125\%}\\\\\dfrac{25}{20}=\dfrac{25}{20}\cdot100\%=25\cdot5\%=\boxed{125\%}
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4 years ago
The cost of 10 oranges is 1.00 what is the cost of 5 dozen oranges
hammer [34]
The answer is 6 dollars, because first you do 1 dollar divided by 10 oranges, which equals 10 cents per orange. Then you do 5 times 12, because a dozen equals 12, which equals 60. Then you do 60 times 10, which equals 600, turn the answer into cents, which 600 cents, and then convert it to dollars. Then you would get an answer of 6 dollars.

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3 years ago
A box contains 10 red marbles, 13 blue marbles, 6 green marbles and 7 white
Zarrin [17]

Answer:

Total number of marbles = 10+20+30 = 60 out of which 20 are blue.

Probability of first marble being blue = 20/60

Probability of second marble being blue = 19/59

Probability of third marble being blue = 18/58

Probability of fourth marble being blue = 17/57

Probability of fifth marble being blue = 16/56

So probability of all marble being blue when five marbles are drawn from the box = (20/60)*(19/59)*(18/58)*(17/57)*(16/56) = 34/11977 = 0.00283877432

Step-by-step explanation:

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What is the lcm of 9 and 7
lesantik [10]

Answer:


Step-by-step explanation:

63

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Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to
djverab [1.8K]

This question is not complete, the complete question is;

Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 5% of the respondents did not provide a response, 26% said that their experience fell short of expectations, and 65% of the respondents said that their experience met expectations. Round your answers to two decimal places.

a. If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations

b. If we chose an alumnus at random, what is the probability that the alumnus would say their experience met or surpassed expectations?

Answer:

a) 0.04

b) 0.69

Step-by-step explanation:    

Given that

P ( No response ) = 5% = 0.05

P ( Short of expectation ) = 26 = 0.26

P ( Met expectation ) = 65% = 0.65

a)  the probability that the alumnus would say their experience surpassed expectations

P ( surpassed expectations) = 1 -  (P(No resp )+P( Short of exp)+ P( Met exp))

= 1 - (0.05 + 0.26 + 0.65 )

= 1 - 0.96

= 0.04

b) the probability that the alumnus would say their experience met or surpassed expectations.

the probability that  experience met or surpassed expectations is;

= P (met exp) + P ( surpassed exp)

= 0.65 + 0.04

= 0.69

 

5 0
3 years ago
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