Answer:
2x^2 + 4x - 64
Step-by-step explanation:
it is telling us to add the functions together so we use this equation:
2x^2 + 7x - 5 + (-8^2) - 3x + 5
after combining like terms we get
2x^2 + 4x -8^2
and then lastly we square the -8 and get
2x^2 + 4x - 64
Answer:
1 I believe.
Step-by-step explanation:
![\frac{x}{x-2} + \frac{x-1}{x+1} =1](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bx-2%7D%20%2B%20%5Cfrac%7Bx-1%7D%7Bx%2B1%7D%20%3D1)
Least common denominator is (x-2)(x+1)
Multiply this times each term.
![(x-2)(x+1)( \frac{x}{x-2} )+(x-2)(x+1)( \frac{x-1}{x+1} )=(x-2)(x+1)(-1)](https://tex.z-dn.net/?f=%28x-2%29%28x%2B1%29%28%20%5Cfrac%7Bx%7D%7Bx-2%7D%20%29%2B%28x-2%29%28x%2B1%29%28%20%5Cfrac%7Bx-1%7D%7Bx%2B1%7D%20%29%3D%28x-2%29%28x%2B1%29%28-1%29)
After cancelling the like factors from numerator and denominator, you get
![(x+1)x+(x-2)(x-1)=(x-2)(x+1)(-1)](https://tex.z-dn.net/?f=%28x%2B1%29x%2B%28x-2%29%28x-1%29%3D%28x-2%29%28x%2B1%29%28-1%29)
Simplify the equation:
![x^2+x+x^2-3x+2=-x^2+x+2](https://tex.z-dn.net/?f=x%5E2%2Bx%2Bx%5E2-3x%2B2%3D-x%5E2%2Bx%2B2)
Add the opposite of all the terms on the right side to each side of the equation:
![3x^2-3x=0](https://tex.z-dn.net/?f=3x%5E2-3x%3D0)
Factor out the GCF:
![3x(x-1)=0](https://tex.z-dn.net/?f=3x%28x-1%29%3D0)
Set each factor equal to zero and solve:
![3x = 0](https://tex.z-dn.net/?f=3x%20%3D%200)
or
![x-1=0](https://tex.z-dn.net/?f=x-1%3D0)
x = 0 or x = 1
After checking each answer in the original equation you will see both numbers work. It's important to check because sometimes the answers can be extraneous (they don't work).
Answer:
Step-by-step explanation:
10p. 39 and z. the terms of 10p+3q+2 are lop, 39 ands In polynomials, each monomial is called the term of the.
Answer:
a) 0.0476
b) 0.1471
c) 0.2252
d) 0.2275
e) 0.1706
f) 0.1013
Step-by-step explanation:
For each bulb, there are only two possible outcomes. Either they are defective, or they are not. This means that we solve this problem using the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
In this problem we have that:
There are 100 bulbs, so
.
3% are defective, so
.
a) 0
![P(X = 0) = C_{100,0}.(0.03)^{0}.(0.97)^{100} = 0.0476](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B100%2C0%7D.%280.03%29%5E%7B0%7D.%280.97%29%5E%7B100%7D%20%3D%200.0476)
b) 1
![P(X = 1) = C_{100,1}.(0.03)^{1}.(0.97)^{99} = 0.1471](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B100%2C1%7D.%280.03%29%5E%7B1%7D.%280.97%29%5E%7B99%7D%20%3D%200.1471)
c) 2
![P(X = 2) = C_{100,2}.(0.03)^{2}.(0.97)^{98} = 0.2252](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20C_%7B100%2C2%7D.%280.03%29%5E%7B2%7D.%280.97%29%5E%7B98%7D%20%3D%200.2252)
d) 3
![P(X = 3) = C_{100,3}.(0.03)^{3}.(0.97)^{97} = 0.2275](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%20C_%7B100%2C3%7D.%280.03%29%5E%7B3%7D.%280.97%29%5E%7B97%7D%20%3D%200.2275)
e) 4
![P(X = 4) = C_{100,4}.(0.03)^{4}.(0.97)^{96} = 0.1706](https://tex.z-dn.net/?f=P%28X%20%3D%204%29%20%3D%20C_%7B100%2C4%7D.%280.03%29%5E%7B4%7D.%280.97%29%5E%7B96%7D%20%3D%200.1706)
e) 5
![P(X = 5) = C_{100,5}.(0.03)^{5}.(0.97)^{95} = 0.1013](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%20C_%7B100%2C5%7D.%280.03%29%5E%7B5%7D.%280.97%29%5E%7B95%7D%20%3D%200.1013)