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Leni [432]
4 years ago
13

Find the exact solutions of the problem algebraically: tan 2x-cot x=0

Mathematics
1 answer:
Eva8 [605]4 years ago
5 0
Tan 2x - cot x = 0
2tan x / (1 - tan^2 x) - 1/tan x = 0
2tan^2 x - (1 - tan^2 x) = 0
2tan^2 x - 1 + tan^2 x = 0
3tan^2 x - 1 = 0
tan^2 x = 1/3
tan x = + or - 1/√3
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What is the slope of the line graphed below??
Burka [1]

We can use the points (1, 2) and (3, -4) to solve.

Slope formula: y2-y1/x2-x1

= -4-2/3-1

= -6/2

= -3

Hope This helped! Good Luck!

8 0
4 years ago
Which of the following expressions is equivalent to 6m - 10?
Natasha_Volkova [10]
Just calculate this:
A) 2(3m + 5) = 6m + 10 - incorrect
B) -2(5 - 3m) = -10 + 6m - could be correct
C) 2(3m - 10) = 63 - 20 - incorrect

So <u>the correct answer has to be B</u>: -10 + 6m is the same as 6m - 10.
3 0
3 years ago
Find the value or measure. Round answers to the nearest tenth, as needed.
kirill115 [55]

Answer:

15

Step-by-step explanation:

10x - 23 + 10x - 23 + 106 = 360

20x + 60 = 360

20x = 300

x = 15

3 0
3 years ago
PLEASE HELP NOW! DUEEE SOONNNN
andrew-mc [135]

Answer:

6^3=6x6x6      3^6=3x3x3x3x3x3 .    5^4=5x5x5x5       4^5=4x4x4x4x4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Fluoxetine, a generic anti-depressant, claims to have, on average, at least 20 milligrams of active ingredient. An independent l
san4es73 [151]

Answer:

t=\frac{18.7-20}{\frac{5}{\sqrt{80}}}=-2.326    

df=n-1=80-1=79  

p_v =P(t_{(79)}  

Step-by-step explanation:

Information given

\bar X=18.7 represent the sample mean for the content of active ingredient

s=5 represent the sample standard deviation for the sample  

n=80 sample size  

\mu_o =20 represent the value that we want to test

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean for the active agent is at least 20 mg, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

The statistic would be:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Now we can calculate the statistic:

t=\frac{18.7-20}{\frac{5}{\sqrt{80}}}=-2.326    

P value

The degrees of freedom are calculated like this:

df=n-1=80-1=79  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(79)}  

6 0
4 years ago
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