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3 years ago

Eight times a number increased by 9 exceeds 7 times the number by 15. Find the number.

Mathematics

2 answers:

Pavel [41]3 years ago

8 0

Remark

Reading the problem is more than 1/2 the trouble you will have with this question.

Start phrase by phrase. Let the number = x

The first phrase is 8 times a number so that is 8x

increased by 9. So that is 8x + 9

exceeds 7 times the number 8x + 9 - 7x

by 15 (translate that to equals 15)

Equation

8x + 9 - 7x = 15 Combine like terms.

x + 9 = 15 Subtract 9

x = 15 - 9

x = 6

Alborosie3 years ago

5 0

Turn it into math terms bit by bit. let x be "a number"

8 times a number is 8×x

increased by 9 is +9

7 times a number is 7×x

exceeds is minus

by 15 is =15

now we put it together.

$8 \times x + 9 - 7 \times x = 15$
solve
$8x + 9 - 7x = 15 \\ x + 9 = 15 \\ x = 6$

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Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

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substitute in equation (2), we get

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it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

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