Rotations. Please help me

What is the best interpretation of the y-intercept of the line?

quester [9]

Answer:

Option D. A student who studies 0 hours can expect to score about a 60 on the test

Step-by-step explanation:

we know that

The y-intercept is the value of the y-coordinate when the value of the x-coordinate is equal to zero

In this problem

The x-coordinate represent the hours spent studying

The y-coordinate represent the Test score

so

For x=0, y=60

That means

A student who studies 0 hours can expect to score about a 60 on the test

3 0

2 years ago

Read 2 more answers

Suppose you have 100 ft of string to rope off a rectangular section for a bake sale at a school Fair. The function A=x^2+50x giv

cupoosta [38]

Answer:

Therefore the width is 25 feet for getting maximum area.

The maximum area of the rectangle is 625 square feet.

Therefore the range is 0≤A≤625.

Step-by-step explanation:

Given function is

A = - x²+50x

We know that ,

If y = ax²+bx+c

For the maximum $x=-\frac{b}{2a}$

Here a = -1 , b= 50 and c=0

Therefore the width $x= -\frac{50}{2.(-1)} = 25$

Therefore the width is 25 feet for getting maximum area.

The maximum area =[ -(25)²+50.25] square feet

= 625 square feet

The area can not be negative and maximum area is 625 square feet.

Therefore the range is 0≤A≤625.

5 0

2 years ago

Darren and barb each tried to evaluate 6(2) + 4 ÷ 2 who elaluated the expression correctly?

arlik [135]

Answer:

14

Step-by-step explanation:

6(2)

12

4÷2

2

12+2

pemdas

7 0

2 years ago

Read 2 more answers

Given a∥b , and c is not parallel to a or b, which statements must be true?

Lana71 [14]

because A & B are parallel

3=7 and 1=8 are true

the first 2 are the only ones that are true

7 0

2 years ago

Read 2 more answers

A simple random sample of 85 students is taken from a large university on the West Coast to estimate the proportion of students

ahrayia [7]

Answer:

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

Step-by-step explanation:

Step(i):-

Given that the sample size 'n' = 85

The sample proportion

$p = \frac{x}{n} = \frac{51}{85} = 0.6$

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

$(p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p(1-p)}{n} })$

Step(ii):-

Given that the level of significance

α = 0.05

Z₀.₀₅ = 1.96

$(0.6 -1.96 \sqrt{\frac{06(1-06)}{85} } , 0.6 +1.96 \sqrt{\frac{0.6(1-0.6)}{85} })$

(0.6 - 0.104138 , 0.6 +0.104138)

(0.4958 , 0.7041)

Final answer:-

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

6 0

2 years ago