Answer:
It would take 86.4 gallons of gas to go 1,836 miles.
Step-by-step explanation:
the situation can be explained by the equation 16x=340, where x is how many miles the car can go in one gallon. divide both sides by 16 to get that answer
x=340/16= 21.25
Now the other problem can be expressed by the equation 21.25y=1836, where y is the amount of gallons it would take to go 1,836 miles.
divide both sides by 21.25 to get the amount of gallons
y= 1836/ 21.25= 86.4.
Answer:
The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 30 - 1 = 29
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.462
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 375 - 41.13 = 333.87 kWh
The upper end of the interval is the sample mean added to M. So it is 375 + 41.13 = 416.13 kWh
The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).
Its Letter B -0.5
negative because its slope is negative (from left to right it's going downward)
so there are 2 negavite numbers in the choices, -0.5 and -0.95.
The nearer the value to 1 the less scatter it is. The farther the value to 1 (means nearer to 0) the more scatter it is. Because the plot in the picture is mostly scattered the value should be nearer to 0. It is negative 0.5.
Answer: The height of the new player is 210 cm
Step-by-step explanation: The previous mean of the entire team has been calculated as 200.3
What this means is that, we have a summation of the observed data and a summation of the frequency of data.
The mean was calculated as
Sum FX/Sum F = 200.3
Where Sum FX is 2604 and Sum F is 13
However, our calculation should now read thus,
Sum FX/Sum F = 201 {where 201 is the new mean}
By cross multiplication we now have
Sum FX = Sum F x 201
Remember that a new member has joined the team so our Sum F is now 14 and we can now express it as thus
Sum FX = 14 x 201
Sum FX = 2814
If the summation of the observed data after adding a new team member is now 2814, then the addition to the previous observed data would be
2814 - 2604 = 210
So the height of the new member added to the team is 210 cm.
