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Naddik [55]
3 years ago
14

How full of water is the glass? 2/3 1/3 2/1 1/2

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0
1/3 full is your answer. :D
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2. The long-jump pit was recently rebuilt to make it level with the runway. Volunteers provided pieces of
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Answer:2. It’s 24.58

How many boards did the volunteers supply round your calculations to the nearest hundred- 13.44

How many whole boards-14

Step-by-step explanation:

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You are a nascar fan that collects cars that are 1:64 scale to the original car. If your collection has cars that are 3 inches i
erik [133]
Length = 3 in * 64 =192
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The true length of a vehicle is 16
good luck and may i be marked as brainliest please
3 0
3 years ago
Read 2 more answers
HELPP PLEASEEEEEEEEEEEEEEEEEEEEEE<br><br> The sum of 6 and 12 divided by 9.
allsm [11]
6 + 12 = 18
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The answer is 2

Hope this helps
3 0
3 years ago
Read 2 more answers
What is 2 to the power of 2?
Tju [1.3M]
Well 2 to the second power would be 2 * 2 which equals 4
8 0
3 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
3 years ago
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