First of all get rid of the parentheses,so it will be 3G-6g-5=-3g-5 I hope that I answered correctly
Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) =
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
Answer:
Therefore,

Step-by-step explanation:
Given:
Consider In Right Angle Triangle ABC
∠B = 90°
∠C = ∠A = 45°
AB = y
BC = x = adjacent side
AC = 8 = hypotenuse
To Find:
x = ?
y = ?
Solution:
In Right Angle Triangle ABC by Cosine Identity we have

substituting the above given values we get


As The triangle is 45 - 45 - 90
It is an Isosceles Right triangle
..... Isosceles Triangle property

Therefore,

Answer:
A
Step-by-step explanation:
180-133= 47
180-142= 38
47+38= 85
180-85= 95
If the inside of n is 95, n has to be 85
Answer:
B(m)=A(m)-D(m)
B(m)=176m
Step-by-step explanation:
we are given
Walking on his own, the distance, D, in feet, that Roberto can cover in M, minutes is given by the function
D(m)=264m
When he walks on the moving sidewalk at the airport, the distance, A, in feet, that he can cover in m m minutes is given by the function
A(m)=440m
B is the distance, in feet, that Roberto would travel on the moving sidewalk in m minutes if he were standing still
moving sidewalk distance = standstill distance + walking distance
A(m)=D(m)+B(m)
so, we get
B(m)=A(m)-D(m)
now, we can plug values
B(m)=440m-264m
B(m)=176m