All categories

3 years ago

The Square Root of a whole number is Always, Sometimes or Never a rational

Mathematics

2 answers:

Igoryamba3 years ago

4 0

The square root of a whole number is rational Sometimes :)

blondinia [14]3 years ago

3 0

The answer is <u>Sometimes</u>

You might be interested in

The standard form of an absolute value function is f(x) = ax-h1+k Which of the following represents the vertex?

blagie [28]

there's no "following"

3 0

2 years ago

Read 2 more answers

Pre cacl pleaseeeee help. the options are in the attachments as well

ivanzaharov [21]

Answer:

The values of $x$ so that $y = \csc x$ have vertical asymptotes are $-2\pi$ , $-\pi$ , $0$ , $\pi$ , $2\pi$ .

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of $x$ so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is $\pi$ . Then, the vertical asymptotes associated with function cosecant are located in the values of $x$ of the form:

$x = 0\pm \pi\cdot i$ , $\forall \,i\in \mathbb{N}_{O}$

In other words, the values of $x$ so that $y = \csc x$ have vertical asymptotes are $-2\pi$ , $-\pi$ , $0$ , $\pi$ , $2\pi$ .

3 0

3 years ago

What is 5-2+(9÷1)×9+0

Anna [14]

The answer is 84 because of process priority

6 0

3 years ago

Read 2 more answers

If two angles of a triangle each measure 45 degrees what is the third angle

8_murik_8 [283]

Since we know that there are exactly 180 degrees in any triangle, and if each angle is equal to 45 degrees, we must add 45 to 45 and then subtract the result from 180 to find the 3rd angle. Since 45+45=90,we subtract 180-90 and get 90 degrees or a right angle.

5 0

3 years ago

Read 2 more answers

find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor

Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: $y = -x^2+8x-12$

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

$y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0$

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

$x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0$

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0

3 years ago