Which proportion can be used to show that the slope of AC is equal to the slope of CE?

Suppose that the probability that a person books an airline ticket using an online travel website is 0.72. Consider a sample of

ExtremeBDS [4]

Answer:

0.183

Step-by-step explanation:

This is a question on Binomial Probability

Formula =nCx × p^x × q^n - x

p = 0.72

q = 1 - p

= 1 - 0.72

= 0.28

x = number of successes = 9

n = 10

The probability that at least nine out of ten people used an online travel website when they booked their airline ticket

At least 9 out of 10 means

x ≥ 9 = x = 9 and x = 10

Hence,

P(x ≥ 9) = 10C9 × (0.72^9 × 0.28^10 - 9) + 10C10 × ( 0.72^10 × 0.28^10 - 10)

P(x ≥ 9) = 0.14559635388 + 0.0374390623

= 0.18303541631

≈ 0.183

3 0

3 years ago

Find the exact solution for the following system of equations. 2x+3y=48 x+6y=11

TEA [102]

Question 2x+3y=48
Answer x = 24 + -1.5y

Question x+6y=11
Answer x = 11 + -6y

4 0

3 years ago

A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current

vladimir2022 [97]

Answer:

$z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5$

Since is a left sided test the p value would be:

$p_v =P(z$

Comparing the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

Step-by-step explanation:

Data given and notation

$\bar X=7.1$ represent the sample mean

$\sigma=1.2$ represent the population standard deviation

$n=36$ sample size

$\mu_o =7.4$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean i lower than 7.4, the system of hypothesis would be:

Null hypothesis: $\mu \geq 7.4$

Alternative hypothesis: $\mu < 7.4$

The statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5$

P-value

Since is a left sided test the p value would be:

$p_v =P(z$

Conclusion

Comparing the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

6 0

3 years ago

Which is the measure of AB? 10 feet 15 feet 20 feet 100 feet

cupoosta [38]

10 feet is the one i hop i help

6 0

4 years ago

Gabe has $100 in a savings account.The interest rate is 5% per year and is not compounded. How much will he have in 1 year?

Damm [24]

Answer:

I believe the answer is $105.

Step-by-step explanation: Because the interest is not compounded, that means that the formula would be 100(.05)(1), and then adding that number (5) to the answer, which is 105.

6 0

3 years ago