Take another photo I can’t see that clearly
Yes with a <span>58,016 Square Kilometers</span>
Yes, this is a polynomial. It is an expression containing variables raised to a real number.
In this case, the variables are being raised to the power of one.
The degree of this polynomial, thus, is one.
The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.
<h3>How to determine the density curves?</h3>
In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:
Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1
Area A = 10 × 0.1
Area A = 1 sq. units (True).
For curve B, we have:
Area B = (3 × 3) × 0.1
Area B = 9 × 0.1
Area B = 0.9 sq. units (False).
For curve C, we have:
Area C = (3 × 4 - 2 × 1) × 0.1
Area C = 10 × 0.1
Area C = 1 sq. units (False).
For curve D, we have:
Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1
Area D = 10 × 0.1
Area D = 1 sq. units (True).
For curve E, we have:
Area E = (1/2 × 4 × 5) × 0.1
Area E = 10 × 0.1
Area E = 1 sq. units (True).
Read more on density curves here: brainly.com/question/26559908
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Answer: The median, because the data distribution is skewed to the left
EXPLANATION
Given the box plot with the following parameters:
Minimum value at 11
First Quartile, Q1 at 22.5
Median at 34.5
Third Quartile, Q3 at 36
Maximum value at 37.5
First, we notice that the data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile
(22.5).
Furthermore, we know that the mean provides a better description of the center when the data distribution is symmetrical while the median provides a better description of the center when the data distribution is skewed.
Therefore, we conclude that for the given box plot, the median will provide a better description of the center because the data distribution is skewed to the left.
