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notka56 [123]
4 years ago
14

By the end of the round 3 of the handshaking activity in the Epidemiology Lab, eight people are infected (of the twenty four peo

ple in your section). What would be the infection rate at the end of the round 4, assuming no one was infected more than once?
a. (8/24) x 100%
b. (14/24) x 100%
c. (15/24) x 100%
d. (16/24) x 100%
e. (24/24) x 100%
Mathematics
1 answer:
Solnce55 [7]4 years ago
4 0

Answer:

d. (16/24) * 100%

Step-by-step explanation:

The infection rate =( Number of infected people/ total number of people) *  100%

After the end of round 3

Infection rate = (8/24)*100%

After the end of round 4, since no one is infected more than once

Infection rate = 2* (8/24)*100%

Infection rate = (16/24) * 100%

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faltersainse [42]
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Misha Larkins [42]

Answer:

14.69% probability that defect length is at most 20 mm

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 28, \sigma = 7.6

What is the probability that defect length is at most 20 mm

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Z = \frac{20 - 28}{7.6}

Z = -1.05

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14.69% probability that defect length is at most 20 mm

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4 years ago
For any nonzero value of a, and for any integers m and n,
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3y – 28 &gt; -9 solve the inequality
Vadim26 [7]

Answer:

y>\frac{19}{3}

Step-by-step explanation:

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Hope this helps.

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anzhelika [568]

Answer:

-1.15

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