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2 years ago

A map has a scale of 1 in. : 25 mi. Two cities are 175 mi apart. How far apart are they on the map?

Mathematics

1 answer:

natulia [17]2 years ago

3 0

Answer:

In inches, this would be 7 inches.

Step-by-step explanation:

Your scale is 1 in.:25 mi, right?

so if we take 175 mi and divide it by 25:

175÷25=7

For so it being 7 inches on your map.

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galina1969 [7]

Answer:

isosceles

Step-by-step explanation:

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3 years ago

--<br> Choose the correct simplification of the expression -5x2(4x – 6x2 – 3).

natali 33 [55]

$\huge \bf༆ Answer ༄$

Let's simply ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: - 5 {x}^{2} (4x - 6 {x}^{2} - 3)$

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${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: - 20 {x}^{3} + 30 {x}^{4} + 15 {x}^{2}$

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2 years ago

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kozerog [31]

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<u></u>

<h3>What is the voter turnout?</h3>

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1 year ago

In ΔSTU, the measure of ∠U=90°, the measure of ∠T=47°, and ST = 7.2 feet. Find the length of US to the nearest tenth of a foot.

Sauron [17]

Answer:

$US=5.3\ ft$

Step-by-step explanation:

we know that

In the right triangle STU

The sine of angle T is equal to the opposite side angle T divided by the hypotenuse

$sin(T)=\frac{US}{ST}$

substitute the values

$sin(47\°)=\frac{US}{7.2}$

$US=(7.2)sin(47\°)=5.3\ ft$

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