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3 years ago

Could someone please help?

Mathematics

2 answers:

melomori [17]3 years ago

4 0

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Gala2k [10]3 years ago

4 0

15. m=26 and n=33. (2m+7=59 and solve)
16. v=45 and w=154. (4v+19=199 and solve)

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Joanna buys a table and 2 chairs. She receives a 25% discount for being a preferred customer and then pays 6% sales tax on the d

Scrat [10]

The total purchase price is $ 357.75

Solution:

Joanna buys a table and 2 chairs

Cost of table = $ 250

Cost of 1 chair = $ 100

Therefore, cost of a table and 2 chairs = 250 + 2(100) = 450

Thus, cost price = $ 450

She receives a 25% discount for being a preferred customer

Therefore, discount = 25 % of cost price

$discount = 25 \% \times 450\\\\discount = \frac{25}{100} \times 450\\\\discount = 0.25 \times 450 = 112.5$

Thus, amount after discount = cost price - discount

amount after discount = 450 - 112.5 = 337.5

Thus, amount after discount is $ 337.5

Then pays 6% sales tax on the discounted purchase price

Sales tax = 6 % of 337.5

$sales\ tax = 6 \% \times 337.5\\\\sales\ tax = \frac{6}{100} \times 337.5\\\\sales\ tax = 20.25$

Thus, total purchase price is given as:

total purchase price = Amount after discount + sales tax

total purchase price = 337.5 + 20.25 = 357.75

Thus total purchase price is $ 357.75

4 0

3 years ago

***I NEED HELP ASAP*** ***Please show all the steps*** ***I will mark brainliest***

mixer [17]

Answer:

First on is 0.75

Second is 22/52 (not sure about this one though)

Step-by-step explanation:

For the first one:

P(aUb) = p(a) + p(b) - p(a^b)

0.6 = 0.4 + 0.5 - p(a^b)

p(a^b) = 0.3

P(a/b)= p(a^b)/p(a)

P(a/b)= 0.3/0.4

P(a/b)= 0.75

For the second one:

Total of the cards are 52

Diamonds are 13 out of that 52

Face cards are 12 out of that 52

Diamond OR face cards means p(aUb)

And that equals p(a)+p(b)-p(a^b)

p(a^b) means the intersection between the two, there are three common cards between diamonds and face cards, so p(a^b)=3

13/52 + 12/52 - 3/52= 22/52

3 0

3 years ago

HELP PLEASE AND THANK YOU 1JAAB

Dafna1 [17]

Answer:

$\bold{Q1}\ side\ BD\\\\\bold{Q2}\ \angle5\ \leftrightarrow\ \angle6\\\\\bold{Q3}\ \triangle TAP\\\\\bold{Q4}\ \triangle APT$

Step-by-step explanation:

For Q1 and Q2

$\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U$

$\overline{AB}\ \leftrightarrow\ \overline{AC}\\\overline{BD}\ \leftrightarrow\ \overline{CD}\\\\\overline{RS}\ \leftrightarrow\ \overline{TU}\\\overline{ST}\ \leftrightarrow\ \overline{UR}$