3 years ago

Could someone please help?

2 answers:

4 0

The pic won’t load

4 0

15. m=26 and n=33. (2m+7=59 and solve)
16. v=45 and w=154. (4v+19=199 and solve)

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____ [38]

1/27
See attached picture

4 0

3 years ago

frez [133]

Accordinly to the details, i think that A could work.

7 0

4 years ago

Novosadov [1.4K]

The answer is 59049 hope this helps

8 0

3 years ago

Llana [10]

Answer: 37

Step-by-step explanation:

Given : Significance level : $\alpha:1-0.98=0.02$

Critical value : $z_{\alpha/2}=z_{0.01}=2.33$

margin of error : E= 1 mile per gallon

Population standard deviation: $\sigma=2.6$ miles per gallon.

We know that when the population standard deviation is known then the formula to find the sample size is given by :

$n=(\dfrac{z_{\alpha/2}\times \sigma}{E})^2$

$n=(\dfrac{(2.33)\times 2.6}{1})^2=36.699364\approx37$ [Round to the next whole number.]

Hence, the required number of automobiles should be used in the test = 37

7 0

4 years ago

sukhopar [10]

-1/2 = -3/6

-3/6 + 1/6 = -2/6

-2/6 = -1/3

-1/3 is your answer

hope this helps

8 0

3 years ago