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liraira [26]
3 years ago
9

Could someone please help?

Mathematics
2 answers:
melomori [17]3 years ago
4 0
The pic won’t load
Gala2k [10]3 years ago
4 0
15. m=26 and n=33. (2m+7=59 and solve)
16. v=45 and w=154. (4v+19=199 and solve)

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A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132
melisa1 [442]
Area = perimeter + 132.  

Let  each side of the city be x miles long, then:-

x^2 = 4x  + 132
x^2 - 4x - 132 = 0

x  =  [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2

x = 13.66, -9.66   We ignore the negative

So the city  has dimension of 13.66 * 13.66

13.7 * 13.7   to nearest 10th
7 0
3 years ago
Plz help... need it quick
erik [133]

Answer:

id say the big triangle and the rectangle

Step-by-step explanation:

sorry if im wrong

4 0
3 years ago
solve for x and y ,32base x+51base y and 23base x +42 base y =710. ,number bases interms of simultaneous equation​
In-s [12.5K]

Answer:

<h2>x = -348.5, y = 350.5</h2>

Step-by-step explanation:

32base x means 3x + 2

Similarly, 32base x+51base y equals to 3x + 2 + 5y + 1 = 3x + 5y + 3

and 23base x +42 base y means 2x + 3 + 4y + 2 = 2x + 4y + 5

As per the given condition, 3x + 5y + 3 = 2x + 4y + 5\\x + y = 2

Putting, y = 2 - x in 2x + 4y + 5 = 710, we get

2x + 4y = 705\\2x + 4(2 - x) = 705\\8 - 2x = 705\\4 - x = 352.5\\x = -348.5

y = 2 - x = 2 - (-348.5) = 2 + 348.5 = 350.5

6 0
4 years ago
Sally has a budget for school stationery of $37, but has already spent $22.72 on books and folders. Let p represent the amount t
dusya [7]

Answer:

p\le 14.28

Step-by-step explanation:

Total budget for school stationery = $37

She has already spent $22.72 on books and folders.

Left amount = $37 - $22.72

= $14.28

Let p represent the amount that Sally can spend on other stationery. It implies that "p" must be less than or equal to $14.28 .

Hence, the required inequality is :

p\le 14.28

4 0
3 years ago
Use the algebra tiles to model x – 2.
choli [55]

Sorry for being late but the answer is B

3 0
3 years ago
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