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Sonbull [250]
3 years ago
10

Which of the following equations is an example of inverse variation between the variables x and y

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0

Answer:

The answer is y = 6/x ⇒ answer A

Step-by-step explanation:

* Lets revise what is the meaning of the inverse variation

- It is a mathematical relationship between two variables

- It can be expressed by an equation in which the product of two

 variables is equal to a constant

- If y is in inverse variation with x

∴ y ∝ 1/x

- Change this relation to equation

∴ y = k/x, where k is the constant of the variation

- We can write it by another way

∵ y ∝ 1/x

∴ y = k/x ⇒ by using cross multiplication

∴ yx = k

* Now lets solve the problem

∵ There is an inverse variation between the two variables x and y

∴ y ∝ 1/x

∴ y = k/x

- Look to the answer

# We will chose A because

∵ y = 6/x  ⇒ use the cross multiplication

∴ yx = 6 ⇒ and 6 is a constant

∴ k = 6

* The answer is y = 6/x

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Answer:

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Step-by-step explanation:

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For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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0.1\sqrt{n} = 2.575{0.25*0.75}

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Rounding up

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