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3 years ago

What property is shown by the equation?

Mathematics

1 answer:

galben [10]3 years ago

6 0

wait what is it i needddd helllpppp

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Find the slope from the table using the slope formula

larisa86 [58]

Answer:

it false

Step-by-step explanation:

7 0

3 years ago

What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)

cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

= 40 * (-2) ^4

= 40 * (16)

= 640

5 0

3 years ago

1. A magazine advertise its $12 annual subscription price 70% off the newsstand price. What is the number of dollars per year a

ollegr [7]

1. $17.14

12 represents 70%
x represents 100%

rule of three

Price Percentage
+12 70-
-x 100+

$x= \frac{12*100}{70} 
 \\ \\
x= \frac{12*10}{7} 
 \\ \\ x=17.14$

3 0

2 years ago

How do we calculate the vertex of a quadratic in standard form?

kvasek [131]

Answer:

y = a $x^{2}$ + b x + c .

Step-by-step explanation:

Also (How to do it!):

We can find the vertex of a quadratic equation with these steps:

Get the equation in the form y = ax2 + bx + c.

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.

6 0

3 years ago

If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90

Eddi Din [679]

Answer:

$90^\circ$

Step-by-step explanation:

Given two non zero vectors, $\vec a, \vec b$ .

Let the angle between the two vectors = $\theta$

Given that:

$|\vec a+\vec b|=|\vec a-\vec b|$

Let us have a look at the formula for magnitude of addition of two vectors:

$|\vec x+\vec y|=\sqrt{x^2+y^2+2xycos\theta}$

Where $\theta$ is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:

$|\vec x-\vec y|=\sqrt{x^2+y^2-2xycos\theta}$

As per the given condition:

$\sqrt{a^2+b^2+2abcos\theta}=\sqrt{a^2+b^2-2abcos\theta}$

Squaring both sides:

$a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ$

So, the angle between the two vectors is: $90^\circ$

7 0

2 years ago