Answer:
1.5 unit^2
Step-by-step explanation:
Solution:-
- A graphing utility was used to plot the following equations:
![f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2](https://tex.z-dn.net/?f=f%20%28%20x%20%29%20%3D%20-%20%5Cfrac%7B4%7D%7Bx%5E3%7D%5C%5C%5C%5Cy%20%3D%200%20%2C%20x%20%3D%20-1%20%2C%20x%20%3D%20-2)
- The plot is given in the document attached.
- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).
- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.
We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).
The double integration formulation can be written as:
![A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2](https://tex.z-dn.net/?f=A%3D%20%5Cint%5Climits_c%5Ed%20%5Cint%5Climits_a%5Eb%20%7B%7D%20%5C%2C%20dy.dx%20%5C%5C%5C%5CA%20%3D%20%5Cint%5Climits_c%5Ed%20%7B%20-%20%5Cfrac%7B4%7D%7Bx%5E3%7D%20%7D%20.%20dx%5C%5C%5C%5CA%20%3D%20%5Cfrac%7B2%7D%7Bx%5E2%7D%20%7C%5Climits_-_2%5E-%5E1%5C%5C%5C%5CA%20%3D%20%5Cfrac%7B2%7D%7B1%7D%20-%20%5Cfrac%7B2%7D%7B4%7D%20%5C%5C%5C%5CA%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20unit%5E2)
Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.
Answer:
im not sure if this is right
Step-by-step explanation:
demension 1: 9 X 10 demension 2: 10 x 4
Answer:
-5/7
Step-by-step explanation:
Slope ,
=(y2-y1)/(x2-x1)
=(-3-2)/(3+4)
=-5/7
The next greater tenth is 14.7
The next smaller tenth is 14.5
Neither of them is nearer to 14.6 than 14.6 already is.
So 14.6 is already the nearest tenth.