Answer:
Here's what I get
Step-by-step explanation:
I plotted the triangles in the diagram below.
Part A
The scale factor for dilation is ½, because every coordinate has been halved.
P (8, 0) ⟶ P' (4, 0)
Q (6, 2) ⟶ Q' (3, 1)
R (-2, -4) ⟶ R' (-1, -2)
Part B
When you reflect a point (x, y) about the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,
P' (4,0) ⟶ P" (-4,0)
Q' (3,-1) ⟶ Q" (-3,-1)
R' (-1,-2) ⟶ R" (1,-2)
∆P"Q"R" has coordinates P" (-4,0), Q" (-3,-1), R"(1,-2).
Part C
∆PQR and ∆ P"Q"R" are not congruent, because corresponding sides are not equal.
Answer:
Step-by-step explanation:
When you factor each equation, you result in two of the factors canceling out, resulting in .
[Top Equation]
The middle number is 3 and the last number is -28.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 3
Multiply together to get -28
Can you think of the two numbers?
Try -4 and 7:
-4+7 = 3
-4*7 = -28
Fill in the blanks in
(x+_)(x+_)
with -4 and 7 to get...
(x-4)(x+7)
[Bottom Equation]
The middle number is -7 and the last number is 12.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -7
Multiply together to get 12
Can you think of the two numbers?
Try -3 and -4:
-3+-4 = -7
-3*-4 = 12
Fill in the blanks in
(x+_)(x+_)
with -3 and -4 to get...
(x-3)(x-4)
An even function implies f(x) = f(-x)
We know that if (6,8) is a point on the graph, then f(6) = 8
By definition, f(6) = f(-6) = 8
So (-6, 8) is also a point on the graph.
1/4q = 3w + 3...multiply both sides by 4
q = 4(3w + 3)
q = 12w + 12 <===
One expression you can do, is to simply simplify the expression,
We can deistribute the 3
6n+9+9
You can then simplify further:
6n+18
Once we have the simplified expression, you can then expnd it in different ways for example:
3(2n+6)
Hope these helped!
