Helppp! pleaseeeeee (solving the system of equations)
1 answer:
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We are given that the angle a is the right angle. So let us work from this.
ab = 12 (the vertical side of the triangle)
bc = 13 (which if drawn can be clearly observed to be the hypotenuse) = the side opposite to angle a
ca = 5 (the horizontal side of the triangle)
Since we are to find for the cosine ratio of angle c or angle θ, therefore:
cos θ = adjacent side / hypotenuse
cos θ = ca / bc
cos θ = 5 / 13
Check out the attached image below for the illustration of the triangle.
Answer:
The equation of the circle having centre (-5,-9) and radius r=3 is
x² + 10 x +y² + 14 y + 65 = 0
Step-by-step explanation:
<u>Explanation</u>:-
From graph The centre of the circle C( -5 , -7)
The radius of the circle r = 3cm from the centre of the given circle
The equation of the circle
From graph the centre ( h, k) = ( -5,-7) and r = 3cm
x² + 10 x +25 +y² + 14 y + 49 =9
x² + 10 x +25 +y² + 14 y + 49 -9=0
The equation of the circle
x² + 10 x +y² + 14 y + 65 = 0