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andreev551 [17]

3 years ago

10

Helppp! pleaseeeeee (solving the system of equations)

1 answer:

Nitella [24]3 years ago

7 0

Answer: x = -3

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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If a rat grows 1.5 inches a year, how many years will it take the rat to grow to 12.3 inches?

vladimir1956 [14]

You would do 12.3/1.5= 8.2 years

7 0

3 years ago

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Estimate the answer to 832.21 + 23.81 by first rounding each number to the nearest tenth.

ycow [4]

852.21+23.81=856.02
so the answer is C) 856

4 0

3 years ago

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What constant do you need to add to each quadratic to complete the square?

babunello [35]

Answer:

1. 4

2. 16

3. 9

Step-by-step explanation:

Completing the square requires a quadratic in $ax^2+bx=c$ form. Once in this form, calculate $(\frac{b}{2})^2$ .

1. $(\frac{b}{2})^2=(\frac{-4}{2})^2=4$

2. $(\frac{b}{2})^2=(\frac{-8}{2})^2=16$

3. Requires you divide everything by 3 first.

$\frac{3x^2+18x}{3} =\frac{249}{3} \\x^2+6x=81$

$(\frac{b}{2})^2=(\frac{6}{2})^2=9$

6 0

3 years ago

Find the distance between the two points in simplest radical form.<br> (-9,8) and (-3, -1)

dmitriy555 [2]

Answer:

The distance between (-9, 8) and (-3, -1) will be:

$\:d=3\sqrt{13}$ units

Step-by-step explanation:

Given the points

(-9, 8)

(-3, -1)

Finding the distance between (-9, 8) and (-3, -1)

$d\:=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-3-\left(-9\right)\right)^2+\left(-1-8\right)^2}$

$=\sqrt{\left(-3+9\right)^2+\left(-1-8\right)^2}$

$=\sqrt{36+81}$

$=\sqrt{117}$

$=3\sqrt{13}$ units

Therefore, the distance between (-9, 8) and (-3, -1) will be:

$\:d=3\sqrt{13}$ units

7 0

3 years ago

Solve the following equations.<br> 3 ⋅ 62^x = 648

gayaneshka [121]

Answer:

$x=1.56861$

Step-by-step explanation:

$62^x=648$

By using logarithms it becomes easier to solve this question because of the properties they have

From the property of logarithms

$loga^x=xloga$

Take logarithms on both sides

$log62^x=log648$

$\Rightarrow xlog62=log648$

$\Rightarrow x=\frac{log648}{log62}$

$\Rightarrow x=1.56861$

$x=1.56861$

7 0

3 years ago